我有一个大问题,我需要你的帮助。
我有一个这样的对象:
{
folder1: {
folderid: 1,
files: {
name: "yeah.txt"
},
folder2: {
folderid: 2
folder3: {
folderid: 3
}
}
},
folder4: {
folderid: 4
}
}
我想搜索密钥" folderid = 3"并找到对象。
我如何在JavaScript中执行此操作?
亲切的问候并感谢您的帮助
答案 0 :(得分:2)
我找到了一个更通用的解决方案,它支持多个属性检查:
function search(obj, properties){
if(Object.keys(properties).every(function(key){
return obj[key] === properties[key];
})) {
return obj;
} else {
Object.keys(obj).forEach(function(key){
var child = obj[key];
if(child !== null && typeof child === 'object'){
return search(child, properties);
}
});
return false;
}
}
答案 1 :(得分:1)
您可以使用DSF算法执行此操作:http://jsfiddle.net/L5b07bt6/
var obj = {
folder1: {
folderid: 1,
files: {
name: "yeah.txt"
},
folder2: {
folderid: 2,
folder3: {
folderid: 3,
caption: "I got it!"
}
}
},
folder4: {
folderid: 4
}
};
function find(root, id) {
if (root.folderid == id) return root;
if (typeof root !== 'object') return null;
var key, val;
for (key in root) {
val = find(root[key], id);
if (val != null) return val;
}
return null;
}
var result = find(obj, 3);
if (!result) alert("Not found!");
else alert("Found: " + result.caption);
答案 2 :(得分:1)
又来了另一个:
function findByKey (object, searchKey){
if(typeof object !== 'object'){
return false;
}
for(var key in object){
if(object[key] === searchKey){
return object;
} else {
if(typeof (object[key] === 'object')){
var result = findByKey(object[key], searchKey);
if(result){
return result;
}
}
}
}
}