Question

在我的应用程序在Android Studio / IntelliJ中的智能手机上编译和部署后，是否可以播放声音

我的解决方法是在我的StartActivity的onStart()方法中播放声音，但我必须为每个新项目实现（复制/粘贴）此模式。不是很好的解决方案。

Answer 1

在Android Studio中，进入偏好设置＆gt;外观＆amp;行为＆gt;通知，请转到Gradle Build（Logging）并选中Read aloud框。

这将说明Gradle构建在x分钟内完成，而构建完成时则为x秒。

Answer 2

不确定它是否可以发出声音，但您可以使用带有gradle的announce plugin来获取通知。检查this article是否开始。通知行为肯定取决于您使用的操作系统..

Answer 3

在mac上根据这个gist和这个answer找到文件夹做：

在speak.gradle文件夹中创建包含以下内容的文件~/.gradle/init.d（如果找不到init.d文件夹，可以创建它）

speak.gradle

// When runnning a Gradle build in the background, it is convenient to be notified immediately 
// via voice once the build has finished - without having to actively switch windows to find out - 
// and being told the actual exception in case of a build failure.

// Put this file into the folder ~/.gradle/init.d to enable the acoustic notifications for all builds

gradle.addBuildListener(new BuildAdapter() {
    
    @Override
    void buildFinished(BuildResult result) {
        def projectName = gradle.rootProject.name
        if (result.failure) {
            playSound('Submarine.aiff')
            def e = getExceptionParts(result)
            "say '$projectName build failed: ${e.first} ${e.second}.'".execute()
        } else {
            if (projectName != "buildSrc") {
                playSound('Glass.aiff')
                "say '$projectName build successful.'".execute()
            }
        }
    }

    private Tuple2<String, String> getExceptionParts(BuildResult result) {
        def exception = result.failure
        if (exception.cause != null) {
            exception = exception.cause
        }
        def className = exception.class.simpleName
        def of = className.indexOf('Exception')
        new Tuple2<String, String>(className.substring(0, of), className.substring(of))
    }

    private void playSound(def sound) {
        "afplay /System/Library/Sounds/$sound".execute()
        sleep(100)
    }
    
})

您可以将声音简化为 done 和 fail

Answer 4

https://stackoverflow.com/a/66226491/8636969 和 https://stackoverflow.com/a/63632498/8636969 的混合，对于 mac 来说非常简单：

gradle.buildFinished { BuildResult buildResult ->
    try {
        "afplay /System/Library/Sounds/Submarine.aiff".execute()
    } catch (Throwable ignored) {}
}

在您的 build.gradle 中。这只会在每次构建完成时播放潜艇声音。

Answer 5

在Windows上，您可以这样做（在build.gradle中）：

gradle.buildFinished { BuildResult buildResult ->
    // Beep on finish
    try {
        String filename = buildResult.getFailure() ? 'Alarm10.wav' : 'Alarm02.wav'
        ['powershell', '-c', """(New-Object Media.SoundPlayer "C:\\Windows\\Media\\${filename}").PlaySync();"""].execute()
    } catch (Throwable ignored) {}
}

Android Studio：关于构建成功的声音通知

5 个答案: