我正在开发一个应用程序,当您以前收到一条短信时,它会向网站发送短信。我的问题是,当我尝试从之前收到的短信发送几条短信...我需要制作一个循环来控制一个字符串数组(msisdn,texto)来检查我收到了多少短信,同时我发送了它们,一个一。有人能帮我吗?谢谢:))
public class GetSMSTask extends AsyncTask<Void, Void, Void> {
private Context mContext;
public GetSMSTask(Context context) {
mContext = context;
}
private static final String SMSBROKER = "http://xx.xx.xx.xx:8080/smsbroker/{params}";
@Override
protected Void doInBackground(Void... arg0) {
OutcomeSms os=new OutcomeSms();
String texto = null;
String msisdn = null;
HashMap<String, List<String>> hash = new HashMap<String, List<String>>();
List<String> list = new ArrayList<String>();
try {
org.apache.http.client.HttpClient client = new DefaultHttpClient();
HttpGet get = new HttpGet(SMSBROKER);
HttpResponse response = client.execute(get);
Log.w("PlaySMSBroker","postSingal Response: " + response.getStatusLine());
os.sendSMSMessage(msisdn, texto, mContext);
list.add(texto);
hash.put(msisdn,list);
List<String> listOfMessages = hash.get(msisdn);
int numberOfMessages = listOfMessages.size();
for (int i=1; i<numberOfMessages; i++){
os.sendSMSMessage(msisdn, texto, mContext);
}
} catch (UnsupportedEncodingException e) {
Log.e("PlaySMSBroker", "UnsupportedEncodingException:" + e.getMessage());
} catch (ClientProtocolException e) {
Log.e("PlaySMSBroker", "ClientProtocolException:" + e.getMessage());
} catch (IOException e) {
Log.e("PlaySMSBroker", "IOException:" + e.getMessage());
} catch (Exception e) {
Log.e("PlaySMSBroker", "Exception" + e.getClass().toString());
}
return null;
}
}
答案 0 :(得分:0)
使用HashMap替换您的数字和法术矩阵。
将电话号码用于hashmap键,并将字符串列表用于hasmap值。
HashMap<a, b> matrix = new HashMap<a, b>();
a =电话号码
b =已发送邮件列表
发送短信时,请在列表中添加条目。如果是第一个sms在hashmap中放置一个。
要查看您发送的短信数量,请按号码获取列表,并计算列表中的项目数。
示例:
//to insert
HashMap<String, List<String>> hash = new HashMap<String, List<String>>();
List<String> list = new ArrayList<String>();
list.add("message1");
hash.put("993739292",list);
//to get list by telefone number
List<String> listOfMessages = hash.get("993739292");
int numberOfMessages = listOfMessages.size();