Question

我已经尝试了在特定列上计算中值的所有可能性，但继续从Excel中获取不同的值。

我正在研究SQL2008R2

这是我到目前为止所尝试的：

SELECT  Entity,
                BillPeriod,
                Cost,
                PatientDays,
                0 AS Median
        FROM GroupCTE
        UNION 
        SELECT  Entity,
                BillPeriod,
                Cost,
                PatientDays,
                0 AS Median
        FROM RegionCTE
                    UNION 
        SELECT  Entity,
                BillPeriod,
                Cost,
                PatientDays,
                0 AS Median
        FROM InstitutionCTE
        Union
        SELECT  'Median' as Entity,
                BillPeriod,
                0 as Cost,
                0 as PatientDays,
                (((
                    (SELECT MAX(Cost) FROM
                        (SELECT TOP 50 PERCENT Cost FROM InstitutionCTE WHERE Cost <> 0 ORDER BY Cost ASC) AS BottomHalf)
                    +
                    (SELECT MIN(Cost) FROM
                        (SELECT TOP 50 PERCENT Cost FROM InstitutionCTE WHERE Cost <> 0 ORDER BY Cost DESC) AS TopHalf)
                )) / 2)  AS Median

我在这里做了一件非常错的事吗？

我试过这个：Function to Calculate Median in Sql Server

谢谢

Answer 1

所以我设法解决了这个问题。问题是，出于某种原因，进行中位数计算得到的结果与Excels中位数函数的结果不同。

我创建了一个TEMP表并导入了我的UNION的结果，然后使用我的计算更新了Median列：

INSERT INTO #Temp
            SELECT  Entity,
                    BillPeriod,
                    ((Cost) / (PatientDays)) * 100 AS Cost,
                    PatientDays,
                    0 AS Median
            FROM GroupCTE
            UNION 
            SELECT  Entity,
                    BillPeriod,
                    ((Cost) / (PatientDays)) * 100 AS Cost,
                    PatientDays,
                    0 AS Median
            FROM RegionCTE
            UNION 
            SELECT  Entity,
                    BillPeriod,
                    ((Cost) / (PatientDays)) * 100 AS Cost,
                    PatientDays,
                    0 AS Median
            FROM InstitutionCTE
            UNION       
            SELECT  'Median' as Entity,
                    BillPeriod,
                    0 AS Cost,
                    0 AS PatientDays,
                    0 AS Median


            FROM InstitutionCTE
            GROUP BY Entity, BillPeriod, PatientDays

            UPDATE #Temp
            SET Median =    ((
                        ((SELECT MAX(Cost) FROM
                            (SELECT TOP 50 PERCENT Cost FROM #Temp WHERE Cost <> 0 ORDER BY Cost ASC) AS BottomHalf)
                        +
                        (SELECT MIN(Cost) FROM
                            (SELECT TOP 50 PERCENT Cost FROM #Temp WHERE Cost <> 0 ORDER BY Cost DESC) AS TopHalf)
                    )) / 2)     


SELECT * FROM #Temp
DROP TABLE #Temp

中位数不正确

1 个答案: