我需要输入驱动循环的帮助,这意味着用户输入两个值,并打印总和,差异,乘积,商和余数,直到用户为第二个值输入零。我不明白如何编写while循环我测试的变量
以下是一个示例:
enter two integers: 19 7
sum of 19 and 7 is 26
difference of 19 and 7 is 12
etc..
答案 0 :(得分:0)
我假设你是初学者......而你正在使用<iostream>
。如果您正在使用其他内容,例如<cstdio>
然后发表评论,我会更改代码,但它是这样的:(对于数字乘法,你可以弄清楚其余部分:D)
#include <iostream>
using namespace std;
int main (){
int num1;
int num2;
while (true){
cout << "Enter some numbers";
cin >> num1 >> num2;
cout << "Product is " << num1*num2;
}
return 0;
}
祝你好运!
答案 1 :(得分:0)
你可以尝试这样的事情。使用无限循环并根据自己的条件打破循环。
#include <iostream>
using namespace std;
int main (){
int num1, num2;
while (1){
cout << "\nEnter some numbers ";
cin >> num1 >> num2;
if(num2==0)
break;
cout << "Product is " << num1*num2;
}
return 0;
}
答案 2 :(得分:0)
使用具有break
条件的无限循环将起到作用。这是如何
#include<iostream>
int main()
{
int a , b;
while( 1 )
{
std :: cout << "\nEnter two integers :" ;
std :: cin >> a >> b ;
if ( b == 0 )
break;
std :: cout << "\nSum of " << a << " and " << b << " is " << a + b ;
std :: cout << "\nDifference of " << a << " and " << b << " is " << a - b ;
std :: cout << "\nProduct of " << a << " and " << b << " is " << a * b ;
std :: cout << "\nQuotient when " << a << " is divided by " << b << " is " << a / b ;
std :: cout << "\nRemainder when " << a << " is divided by " << b << " is " << a % b ;
}
return 0;
}
如果break
,您只需使用b == 0
即可。遇到break
时,程序退出循环。 (如果你是一个总菜鸟并且不知道如何使用休息,请阅读break)
while( 1 )
是一个无限循环,程序只会在遇到break
时退出循环。
还要记住,%
不会在浮动上工作。如果你想要浮点数,那么你必须使用std::fmod()(std :: fmod( a , b );
返回余下的a
除以b
,其中a
和{{1}是浮点数或双精度数,它包含在b
头文件中。)
答案 3 :(得分:0)
这可以通过多种方式完成。例如
while ( true )
{
std::cout << "Enter two integer numbers: ";
int first;
int second = 0;
std::cin >> first >> second;
if ( second == 0 ) break;
std::cout << "sum of " << first
<< " and " << second
<< " is " << first + second;
<< std::endl;
std::cout << "difference of " << first
<< " and " << second
<< " is " << first - second;
<< std::endl;
// and other outputs if they are required
}