Question

我想有一个UIView阻止子视图以响应手势。主要目的是在服务器中验证数据时阻止用户界面接触和手势。处理完请求后，它将从阻止UIView的顶部删除。

如何实现这一目标？到目前为止我所拥有的是：

@interface TableViewController ()
    @property (weak, nonatomic) IBOutlet UITableView *table;
    @property (strong, nonatomic) IBOutlet UIView *blockingScreen;
    ....
@end

实施：

@implementation PlayListViewController

    - (void)viewDidLoad
    {
        [super viewDidLoad];
        _table.dataSource      = self;
        _table.delegate        = self;

        // Blocking screen should take all the screen. 
        // Unfortunately, when it is displayed it gets the table size , ??
        _blockingScreen = [[UIView alloc] initWithFrame:CGRectMake(0,0,
                                         [[UIScreen mainScreen] applicationFrame].size.width,
                                         [[UIScreen mainScreen], applicationFrame].size.height)];

        _blockingScreen.userInteractionEnabled = NO;

        [self loadGestureRecognizer];
    }

    - (void) loadGestureRecognizer
    {
        // Long press gesture recognizer declaration
        UILongPressGestureRecognizer *longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPressGestureRecognized:)];

        // Swipe gesture recognizer declaration
        UISwipeGestureRecognizer *swipeLeftGesture = [[UISwipeGestureRecognizer alloc] initWithTarget:self action:@selector(swipeGestureRecognizer:)];
        swipeLeftGesture.direction = UISwipeGestureRecognizerDirectionLeft;

        // Attach gesture recognizers
        [_songsTable addGestureRecognizer:longPress];
        [_songsTable addGestureRecognizer:swipeLeftGesture];
    }

    // At some point, the gesture recognizer will be invoked
    // In this case when swiping a table row
    - (IBAction)swipeGestureRecognizer:(UISwipeGestureRecognizer *)sender 
    {
        // Do things
        ...

       // Preparing for doing Http request
       // I want to display the blockingScreen on top of all views
       // so no gestures are recognized.
       [_table addSubview:_blockingScreen];
       [_blockingScreen setBackgroundColor:[UIColor blackColor]];
       _blockingScreen.alpha = 0.3;

       // Bring to front
       [_table bringSubviewToFront:_blockingScreen];

       // To avoid gesture recognition I'm forced to do the following
       _table.userInteractionEnabled = NO;
    }
@end

在某些时候，swipeGestureRecognizer将通过滑动手势调用。这很好用。 blockingScreen似乎位于表格视图的顶部（仅仅是表格）并且不会阻止任何手势。

我对objective-c和xcode很新，所以欢迎解释，教程或外部资源。我已经在其中阅读了其他一些答案，例如How to disable touch input to all views except the top-most view?，Container View Receives Touches Instead of Subview on iPad并尝试过：

_blockingScreen.userInteractionEnabled = NO;

还要

_blockingScreen.userInteractionEnabled = YES;

并没有看到任何差异。

任何人都有任何想法？

Answer 1

通过在执行处理时忽略交互事件，可以更轻松地完成此任务。

[[UIApplication sharedApplication] beginIgnoringInteractionEvents];

// Do all the things

[[UIApplication sharedApplication] endIgnoringInteractionEvents];

documentation中的更多信息。

Answer 2

手势识别器位于视图上方

来自docs：“一个窗口将触摸事件传递给手势识别器，然后将其传递到连接到手势识别器的经过测试的视图。”

所以......视图并没有真正禁用手势识别器 =＆GT;禁用它：regconizer.enabled = false

Answer 3

你可以这样首先，您必须管理isValidated或不使用，然后像这样使用 1.解决方案

-(BOOL) gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch
{
     if (isValidated)
     {
         return YES;  
     }else{
          if(gestureRecognizer.view == songsTable) return NO;
     }
     return YES;
}

解您可以在调用服务器数据时禁用用户的交互。您可以在从服务器获得响应时启用。

我希望它可以帮助你

Objective-C - 使用子视图在验证数据时阻止触摸或手势

3 个答案:

手势识别器位于视图上方