Question

嗨伙计们。我有这个问题。我试图解决但我无法解决。它是关于ajaxSubmit函数的。

$(this).ajaxSubmit({
            url: 'url',
            dataType: 'json',
            cache: 'false',
            beforeSend: function(){
                alert('before')
            },
            success: function(data){
                alert('success')
            },
            error: function(data) {
                console.log(data);
            },
 });

始终通过以下方式访问错误案例：

Object {aborted: 0, responseText: "{"success":false,"error_message":"<p>The 

Title fie…:"The Introduction text field is required."}}</p>", responseXML: document, status: 0, statusText: "n/a"…}abort: function (status) {aborted: 0error: SyntaxError: Unexpected token <getAllResponseHeaders: function () {}getResponseHeader: function (header){responseText: "{"success":false,"error_message":"<p>The Title field is required.&lt;\/p&gt;\n</p><p>The Introduction text field is required.&lt;\/p&gt;\n","error_fields":{"title":"The Title field is required.","intro_text":"The Introduction text field is required."}}</p>"responseXML: nullsetRequestHeader: function () {}status: 0statusText: "n/a"__proto__: Object

和控制器响应

{"success":false,"error_message":"<p>The Title field is required.<\/p>\n<p>The Introduction text field is required.<\/p>\n","error_fields":{"title":"The Title field is required.","intro_text":"The Introduction text field is required."}}

Answer 1

尝试使用此代码。

$(this).ajaxSubmit({
    type: "POST", // Enter Request type GET/POST
    url: 'action.php', // Enter your ajax file URL here,
    dataType: 'json', // If you are using dataType JSON then in php file use die( json_encode($resultArray) );
    cache: 'false',
    data: {_keyName: "abcd"}, // Put your values here
    beforeSend: function(){
        alert('before')
    },
    success: function(data){
        alert('success')
    },
    error: function(data) {
        console.log(data);
    }
 });

告诉我其他什么

Answer 2

检查服务器端的代码，因为客户端没有错误

尝试以下步骤：

1-打印任何透明的东西，例如：回声“测试”

2-如果您没有错误，请检查您的回复数据，因为，我猜你错过了逗号或以错误的方式添加了html元素

Answer 3

$(this).ajaxSubmit({
    type: "POST", // Enter Request type GET/POST
    url: 'action.php', // Enter your ajax file URL here,
    dataType: 'json', // If you are using dataType JSON then in php file use die( json_encode($resultArray) );
    cache: 'false',
    data: {_keyName: "abcd"}, // Put your values here
    beforeSend: function(){
        alert('before')
    },
    success: function(data){
        alert('success')
    },
    error: function(data) {
        console.log(data);
    }
 });

ajaxSubmit错误情况

3 个答案: