Question

我想忽略生产的第一天是否有任何零值。

SELECT D_DATE, PRODUCE FROM PRODUCTION

数据集

Date         Produce
1/1/2015        0
1/2/2015        0
1/3/2015        0
1/4/2015        6
1/5/2015        5
1/6/2015        2
1/7/2015        0
1/8/2015        1
1/9/2015        1

前三天是我想在结果中忽略的零，但第7天不应该被忽略

期望的结果

Date         Produce
1/4/2015        6
1/5/2015        5
1/6/2015        2
1/7/2015        0
1/8/2015        1
1/9/2015        1

Answer 1

为简单起见，我假设至少有一天有产品＆gt; 0

SELECT d_date, produce
FROM production
WHERE
    d_date >= (
        SELECT MIN(d_date)
        FROM production
        WHERE
            produce != 0
    )
;

Answer 2

您可以使用SUM作为分析函数来计算产生的累积总和并过滤大于零的那些。

select d_date, produce
from (
        select 
        d_date, 
        produce, 
        sum(produce) over (order by d_date) cuml_produce
        from production
)
where cuml_produce > 0
order by d_date;

Answer 3

试试这个

SELECT date,
       produce
FROM
(
SELECT date,
       produce,
       row_number() over (order by date) r1,
       row_number() over (order by produce, date) r2
FROM  production
) A
WHERE r1 != r2

Answer 4

使用相关子查询。

SELECT Date, Produce, 
ROW_NUMBER() OVER (ORDER BY DATE) RN 
INTO #Temp
FROM tbl

SELECT t.Date, t.Produce  FROM #Temp t
WHERE 
 EXISTS(
                 SELECT 1 FROM #Temp t1 
                  WHERE t1.rn < t.rn
                  AND t1.PRODUCE !=0)
OR T.Produce != 0

Fiddle here

Answer 5

假设您的日期在DATETIME，这会对您有所帮助吗？

SELECT D_DATE, PRODUCE
FROM PRODUCTION
where  Date  >= (select TOP 1 Date from PRODUCTION where PRODUCE > 0 Order by DATE)

如何忽略查询结果中的第一个零

5 个答案: