第一次尝试从JSON文件中检索数据时,老老实实地不知道如何获取我想要的对象。
有人可以告诉我如何获取Family Name
或familyAttributes
等值?我根本不知道如何处理数据。
当前的AJAX通话
$.ajax({
type: 'GET',
url: 'https://somesite.com/EloMS.json',
data: { category : 'Touchmonitors' },
dataType: 'json',
success: function(data) {
$.each(data, function(index, element) {
console.log(element);
});
}
});
JSON语法:
{
"products": [
{
"Family Name": "3201L",
"Type": "IDS",
"Size (inches)": 32,
"Aspect Ratio": "16:9",
"Part Number": "E415988",
"Product Description": "ET3201L-8UWA-0-MT-GY-G",
"Marketing Description": "3201L 32-inch wide LCD Monitor, VGA, HDMI & DisplayPort video interface, 01 series enhanced AV, IntelliTouch Plus USB touch controller interface, Worldwide-version, Clear, Gray ",
"Advance Unit Replacement": "",
"Elo Elite": "",
"Package Quantity": 1,
"Minimum Order Quantity": 1,
"List Price": 1800
},
{ ... }
]
"families": [
{
"category": "Touchmonitors",
"types": [
"Desktop",
"Display",
"Open Frame"
],
"image": "",
"familyAttributes": [
{
"type": "Display",
"image": "",
"families": [
{
"familyName": "0700L",
"image": ""
}
]
},
{ ... }
}
]
}
我尝试了element.category
的几种变体,但除了完整的对象之外,还无法获得任何数据。
答案 0 :(得分:1)
对于product
对象,您需要:
data.products[n]["Family Name"]
其中n
是products
数组的整数偏移量。
对于familyAttributes
,您需要:
data.families[n].familyAttributes
由于密钥中的空格字符,第一种情况下需要["string"]
语法。
答案 1 :(得分:-1)
你可以使用getJSON(),文档在这里: http://api.jquery.com/jquery.getjson/
您可以像这样访问您的模型:
$.getJSON('https://somesite.com/EloMS.json', function(data) {
// Products table
var products = data.products;
// Product type
var typeProduct = data.products[0].Type;
// familyAttributes
var familyAttributes = data.families[0].familyAttributes;
// Family Name
var familyName = data.products[0]['Family Name'];
});