Question

我从FPGA接收字节并且它出现在textbox4中，但是，因为我的输出是（例如：0x03或0x07 ...），文本框中出现的是奇怪的符号（我认为是ASCII表示0x03）： the interface

所以我想要的是输出只是3（十进制值0x03），我该怎么办？我尝试了很多（参见我的代码的textbox5），但我不能，你能帮助初学者吗？谢谢。注意：我的FPGA计算M ^ e mod G-> 33 ^ 5 mod 35 = 3 - 代码：

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.IO;

namespace WindowsFormsApplication1
{
    public partial class Form2 : Form
    {


        public Form2()
        {
            InitializeComponent();
        }

        string RXstring = "";


        private void pictureBox2_Click(object sender, EventArgs e)
        {
            serialPort1.Close();
            Form1 myForm = new Form1();
            this.Close();


        }

        private void groupBox1_Enter(object sender, EventArgs e)
        {

        }

        private void button3_Click(object sender, EventArgs e)
        {
            try
            {
                if (!serialPort1.IsOpen)
                {

                    serialPort1.Open();
                    button3.Enabled = false;
                }
                else
                {
                    MessageBox.Show("Port is Open by other party!");

                }


            }
            catch (UnauthorizedAccessException ex)
            {
                MessageBox.Show(ex.Message);
            }
        }

        private void Form2_FormClosed(object sender, FormClosedEventArgs e)
        {
            serialPort1.Close();
        }

        private void serialPort1_DataReceived(object sender, System.IO.Ports.SerialDataReceivedEventArgs e)
        {
            try
            {
                RXstring = serialPort1.ReadExisting();
                this.Invoke(new EventHandler(displaytext));
            }
            catch (System.TimeoutException)
            {

            }

            }
        private void displaytext(object s, EventArgs e)
        {
            //var a = RXstring[0];
            //var b = RXstring[1];
            //string h = String.Format("{0:X2}", RXstring);
             textBox4.AppendText(RXstring);


        }

        void button1_Click(object sender, EventArgs e)
        {
            //Get the strings (text)
            string textM = textBox1.Text;
            string textE = textBox2.Text;
            string textG = textBox3.Text;

            //Assuming you want unsigned numbers, convert to numeric types
            //You might want to put in exception handling for invalid inputs, watch for overflows etc.
            UInt16 bitsX = Convert.ToUInt16(0x1F01);
            UInt16 bitsM = Convert.ToUInt16(textM);
            UInt16 bitsE = Convert.ToUInt16(textE);
            UInt16 bitsG = Convert.ToUInt16(textG);


            /*
             * BitConverter puts the LSB at index 0, so depending on how you need to send the data,
             * you might want to reverse the bytes BitConverter.GetBytes(bitsM).Reverse();
             * or reverse the order you add them to the list
             */
            var byteList = new List<byte>();
            byteList.AddRange(BitConverter.GetBytes(bitsX));
            byteList.AddRange(BitConverter.GetBytes(bitsM));
            byteList.AddRange(BitConverter.GetBytes(bitsE));
            byteList.AddRange(BitConverter.GetBytes(bitsG));

            //Debugging message, uses LINQ 
            string bits = String.Join(" ",byteList.Select(b => b.ToString("X2")));
            MessageBox.Show(bits);


            //write the bytes
            var bitArray = byteList.ToArray();
            serialPort1.Write(bitArray, 0, 8);
            //var x = bitArray[1] + (bitArray[2] << 0) + (bitArray[3] << 0) + (bitArray[4] << 0) + (bitArray[5] << 0) + (bitArray[6] << 0) + (bitArray[7] << 0);

            //string y = String.Format("{0:X2}", x);
            //string y = System.Text.Encoding.UTF8.GetString(bitArray);
            //textBox5.AppendText(y);

        }

        private void button2_Click(object sender, EventArgs e)
        {
            textBox1.Text = "";
            textBox2.Text = "";
            textBox3.Text = "";
            textBox4.Text = "";
        }

        private void textBox5_TextChanged(object sender, EventArgs e)
        {
            var value = Convert.ToInt16(textBox4);
            string ss = value.ToString();

            MessageBox.Show(ss.ToString());
            string stringValue = Char.ConvertFromUtf32(value);

            decimal vOut = Convert.ToDecimal(textBox4);
            textBox5.AppendText(vOut.ToString());
        }
    }
}

Answer 1

您的代码尝试将十六进制字符串（如：1234567890ABCDEF）转换为字节数组。查看它的简化版本

string M = "2A";
byte b = Convert.ToByte((M.Substring(0, 2)), 16);

将以十进制显示42。

您可以使用.NET中的内置类轻松完成此操作

byte[] data = SoapHexBinary.Parse(M).Value;

PS： SoapHexBinary 在System.Runtime.Remoting.Metadata.W3cXsd2001命名空间

Answer 2

我将逻辑分解为几个步骤：

获取文字
将文本解析为数字（二进制）
将字节添加到列表中。
将List<byte>隐藏到阵列并发送到串口

我已对以下部分发表了评论。我使用Convert和BitConverter来帮助转换。此代码特意详细，以帮助显示详细信息。

void button1_Click(object sender, EventArgs e)
{
    //Get the strings (text)
    string textM = textBox1.Text;
    string textE = textBox2.Text;
    string textG = textBox3.Text;

    //Assuming you want unsigned numbers, convert to numeric types
    //You might want to put in exception handling for invalid inputs, watch for overflows etc.
    UInt16 bitsM = Convert.ToUInt16(textM);
    byte bitsE = Convert.ToByte(textE);
    UInt32 bitsG = Convert.ToUInt32(textG);


    /*
     * BitConverter puts the LSB at index 0, so depending on how you need to send the data,
     * you might want to reverse the bytes BitConverter.GetBytes(bitsM).Reverse();
     * or reverse the order you add them to the list
     */
    var byteList = new List<byte>();
    byteList.AddRange(BitConverter.GetBytes(bitsM));
    byteList.AddRange(BitConverter.GetBytes(bitsE));
    byteList.AddRange(BitConverter.GetBytes(bitsG));

    //Debugging message, uses LINQ 
    string bits = String.Join(" ", byteList.Select(b => b.ToString("X2")));
    MessageBox.Show(bits);


    //write the bytes
    var bitArray = byteList.ToArray();
    serialPort1.Write(bitArray, 0, 7);
}

Answer 3

在某个点的for循环中，x + 2变得大于字符串M的长度，从而导致错误。要摆脱它，将第一个for循环更改为：

 for (i = 3; i < 13; i++)
 {
      if(x + 2 <= M.Length)
      {
          data[i + 1] = Convert.ToByte((M.Substring(x, 2)), 16);
          x += 2;
      }
  }

编辑 -
你提到输入是1s和0s的形式，这使得它是二进制的，在这种情况下将上面改为：

Convert.ToByte((M.Substring(x, 2)), 2);

<小时/> 正如IV4正确指出的那样更新 - 您正在尝试将二进制字符串转换为字节，但代码意味着将十六进制字符串转换为字节需要修改代码以便相应地工作。

 for (i = 3; i < 13; i++)
     {
          if(x + 8 <= M.Length)
          {
              data[i + 1] = Convert.ToByte((M.Substring(x, 8)), 2);
              x += 8;
          }
      }

在文本框中显示Char的十进制值

3 个答案: