如何在字符串中查找特殊字符并将其替换为SQL中的空格?

时间:2015-03-18 18:53:36

标签: sql sql-server sql-server-2012

我有contact_firstname列,在该列中存储的数据中有一些特殊字符,如(@,&, - ,_等)。我想首先在每个记录中找到所有这些特殊字符,并用空格替换这些字符。我在这个网站上找到了一个查询,它有助于识别特殊字符,但我不知道如何在下面的字符串中找到每个特殊字符的charindex并用空格替换它。

DECLARE @MyString VARCHAR(100)
SET @MyString = '!Char$Fox@'

IF (@MyString LIKE '%[^a-zA-Z0-9]%')
   BEGIN
      PRINT 'Contains "special" characters'

    END

2 个答案:

答案 0 :(得分:0)

我认为你必须循环,正如Tab Alleman所说:

declare @MyString varchar(100) = '!Char$Fox@'
declare @i int = 0
declare @char varchar(1)
declare @len int = LEN(@MyString)
declare @result varchar(100) = ''

while @i < @len
begin
    set @char = SUBSTRING(@MyString, @i, 1)

    if @char like '%[^a-zA-Z0-9]%'
    begin
        set @char = ' '
    end

    set @result = @result + @char
    set @i = @i + 1
end

select @result

答案 1 :(得分:0)

你也可以这样做:

DECLARE @InvalidChars VARCHAR(100)
DECLARE @MyString VARCHAR(100)

SET @InvalidChars = '!$@'
SET @MyString = '!Char$Fox@'

;WITH CTE AS
(
  SELECT SUBSTRING(@InvalidChars, 1, 1) AS [String], 1 AS [Start], 1 AS [Counter]
  UNION ALL
  SELECT SUBSTRING(@InvalidChars, [Start] + 1, 1) AS [String], [Start] + 1, [Counter] + 1 
  FROM CTE 
  WHERE [Counter] < LEN(@InvalidChars)
)

SELECT @MyString = REPLACE(@MyString, CTE.[String], ' ') FROM CTE

SELECT @MyString

结果:

  

Char Fox

这是以下解决方案的组合:

How to Replace Multiple Characters in SQL?

T-SQL: Opposite to string concatenation - how to split string into multiple records [duplicate]