Question

我正在尝试创建一个表来计算各个办事处每个职位的出现次数。

所以，如果我的数据如下：

Office Position
A      Manager
A      Supervisor
A      Entry Level
A      Entry Level
B      Manager
B      Entry Level

我希望我的代码返回：

Office    Managers    Supervisors     EntryLevel
A            1             1              2
B            1             0              1

我的代码如下。问题是此代码计算总发生次数，而不是每个办公室的唯一计数。结果如下

A   2   1   3
B   2   1   3

CREATE TABLE OfficeTest AS
SELECT DISTINCT Office,
(Select COUNT(Position) FROM OfficeData  WHERE Make_Name = 'Manager') as Managers, 
(Select COUNT(Position) FROM OfficeData  WHERE Make_Name = 'Supervisor') as Supervisors,
(Select COUNT(Position) FROM OfficeData  WHERE Make_Name = 'Entry Level') as EntryLevel

FROM OfficeData 
GROUP BY Office;

有关如何解决此问题的任何想法？

Answer 1

我能想到的最简单的方法就是这样：

SELECT Office,
       COUNT(CASE WHEN Make_Name = 'Manager' THEN Position END) AS Managers,
       COUNT(CASE WHEN Make_Name = 'Supervisor' THEN Position END) AS Supervisors,
       COUNT(CASE WHEN Make_Name = 'Entry Level' THEN Position END) AS EntryLevel
FROM OfficeData
GROUP BY Office

COUNT忽略MISSING个值;如果Position不是CASE子句中指定的值，则会返回MISSING值并且不会被计算在内。这样每种情况都只考虑您比较的Position的值。

如评论中所述，另一个选择是转动表格。 SAS等效项是TRANSPOSE过程。我没有SAS系统来使用它来创建和测试查询，但here's the documentation以防您想要查看它。

Answer 2

只是为了清除Danny的评论，SUM代码看起来像：

proc sql;
    CREATE TABLE want AS
    SELECT office,
    SUM( (position='Manager') ) as Managers,
    SUM( (position='Supervisor') ) as Supervisors,
    SUM( (position='Entry Level') ) as EntryLevel
FROM OfficeData
GROUP BY office
;quit;

(position='Manager')位解析为0或1，具体取决于当前记录的true是否为真。我发现SUM版本更简洁，更清晰，但两者都适用于您的情况。此外，它可以轻松扩展到多个标准，例如(postion='Manager')*(sex='F')，只计算女性经理。

Answer 3

SUM与CASE语句应解决此问题。以下是参考代码

proc sql;
create table result as 
select age
      , sum(case sex when 'F' then 1 else 0 end) as Female
      , sum(case sex when 'M' then 1 else 0 end) as Male
from sashelp.class
group by age;
quit;
proc print data=result;run;

SQL计数表达式

3 个答案: