如何检查数组中的所有内容是否相同？使用swift

Question

我有一个不断更新的数组。我如何检查所有内容是否相同？对于前。

var Array:[String] = ["1", "2", "1", "1", "1", "2"]

if //all array contents are equal to 1 {

println("Array = 1")

}

感谢

Answer 1

更好的解决方案是使用集合

//var set = NSSet(array: [2,3,3,2,1])
var set = NSSet(array: [1,1,1,1,1])

if set.count == 1 {
    println("All the same")
}

Answer 2

这只是一个例子，只是为了说明一种方法：

var myArray = ["1","1","2","1"]

func checkOut(array: [String]) -> Bool {
var number = 0

for index in 0..<array.count {
    if array[index] == "1" {
        number++
    }
}

if number == array.count {
    return true }
else {
    return false }
}

checkOut(myArray)

Answer 3

标题问题：＆＃34;检查所有元素是否相等＆＃34;

    //let array = ["1", "2", "1", "1", "1", "2"]
    let array = ["1", "1", "1", "1", "1", "1"]

    //just check if all elements *equal*
    let set = NSSet(array: array)
    if set.count == 1 {
        println("all elements equal")
    }

代码问题：检查元素是否等于X

    //just check if all elements are equal to X
    let set = NSSet(array: array)
    if(set.count == 1) {
        let myObj = set.anyObject() as String!
        let equalTo = "1"
        if  myObj == equalTo {
            println("all elements equal 1")
        }
    }