我试图以动态方式将对象属性添加到数据表中。我试图远离显式声明对象的属性,因为我希望此代码适用于我的应用程序中的每个对象。 我已经阅读了Adding object to DataTable and create a dynamic GridView,但这对我来说不够动态,因为他明确指定了属性。
private static void Main(string[] args)
{
//Read in JSON from text file
StreamReader fileStream = new StreamReader(@"C:\Users\Aid\Desktop\test.txt");
string json = fileStream.ReadToEnd();
//Deserialise and map to class
Client u = JsonConvert.DeserializeObject<Client>(json);
DataTable dt = new DataTable();
List<string> CliProperties = new List<string>();
//Loop through Object properties and add to Datatable columns
CliProperties = objProps(u);
DataRow newRow = dt.NewRow();
foreach (var prop in CliProperties)
{
dt.Columns.Add(prop);
newRow[prop] = u.prop;
}
Console.ReadKey();
}
/// <summary>
/// Get list of object properties
/// </summary>
/// <param name="obj"></param>
/// <returns></returns>
public static List<string> objProps(Object obj)
{
List<string> Props = new List<string>();
Type objType = obj.GetType();
foreach (PropertyInfo propertyInfo in objType.GetProperties())
{
if (propertyInfo.CanRead)
{
Props.Add(propertyInfo.Name);
}
}
return Props;
}
}
public static class DataColumnCollectionExtensions
{
public static IEnumerable<DataColumn> AsEnumerable(this DataColumnCollection source)
{
return source.Cast<DataColumn>();
}
}
我的问题是:
foreach (var prop in CliProperties)
{
dt.Columns.Add(prop);
newRow[prop] = u.prop;
}
我收到错误:'Client' does not contain a definition for 'prop' and no extension method 'prop' accepting first argument of type 'Client'
我理解为什么我会收到错误,但我不确定如何使其发挥作用。
我尝试使用对象属性值newRow[prop]
的值添加PropertyName = u.prop
的新行。
编辑:DataTable列名称将与对象属性名称相同。
foreach的第一次迭代应该如下:
foreach (var prop in CliProperties)
{
dt.Columns.Add("RefID");
newRow["RefID"] = u.RefID;
}
答案 0 :(得分:3)
使用针对列表的此扩展方法,将User
对象设为List<User>
,然后只需在其实例上调用ToDataTable()
。
这是扩展方法:
public static class ListExtensions
{
public static DataTable ToDataTable<T>(this List<T> iList)
{
DataTable dataTable = new DataTable();
PropertyDescriptorCollection propertyDescriptorCollection =
TypeDescriptor.GetProperties(typeof(T));
for (int i = 0; i < propertyDescriptorCollection.Count; i++)
{
PropertyDescriptor propertyDescriptor = propertyDescriptorCollection[i];
Type type = propertyDescriptor.PropertyType;
if (type.IsGenericType && type.GetGenericTypeDefinition() == typeof(Nullable<>))
type = Nullable.GetUnderlyingType(type);
dataTable.Columns.Add(propertyDescriptor.Name, type);
}
object[] values = new object[propertyDescriptorCollection.Count];
foreach (T iListItem in iList)
{
for (int i = 0; i < values.Length; i++)
{
values[i] = propertyDescriptorCollection[i].GetValue(iListItem);
}
dataTable.Rows.Add(values);
}
return dataTable;
}
}
你必须简单地这样说:
List<User> users = new List<User>();
DataTable dt = users.ToDataTable();
您的方式必须迭代User
类属性,如下所示:
PropertyDescriptorCollection propertyDescriptorCollection =
TypeDescriptor.GetProperties(typeof(User));
for (int i = 0; i < propertyDescriptorCollection.Count; i++)
{
PropertyDescriptor propertyDescriptor = propertyDescriptorCollection[i];
Type type = propertyDescriptor.PropertyType;
if (type.IsGenericType && type.GetGenericTypeDefinition() == typeof(Nullable<>))
type = Nullable.GetUnderlyingType(type);
dt.Columns.Add(propertyDescriptor.Name, type);
}
刚刚为Class
的单个对象编写了另一种扩展方法:
public static DataTable ToDataTable<T>(this T Item) where T: class
{
DataTable dataTable = new DataTable();
PropertyDescriptorCollection propertyDescriptorCollection =
TypeDescriptor.GetProperties(typeof(T));
for (int i = 0; i < propertyDescriptorCollection.Count; i++)
{
PropertyDescriptor propertyDescriptor = propertyDescriptorCollection[i];
Type type = propertyDescriptor.PropertyType;
if (type.IsGenericType && type.GetGenericTypeDefinition() == typeof(Nullable<>))
type = Nullable.GetUnderlyingType(type);
dataTable.Columns.Add(propertyDescriptor.Name, type);
}
object[] values = new object[propertyDescriptorCollection.Count];
for (int i = 0; i < values.Length; i++)
{
values[i] = propertyDescriptorCollection[i].GetValue(Item);
}
dataTable.Rows.Add(values);
return dataTable;
}
并将其称为:
Client u = JsonConvert.DeserializeObject<Client>(json);
DataTable dt = user.ToDataTable();