Question

我读过几个问题，例如MySQL grouping by week, based on a date column?。

但我的日期类型为int（11）（我无法更改结构）以存储类似 20150101 的内容来代表 2015年1月1日。我应该如何使用WEEK方法根据此进行分组？

像：

select week(SOMETHING_TO(dateid)) as weeknum, game ,count(*) 
from table where game is not null group by weeknum , game order by weeknum desc;

Answer 1

我认为您需要先将int(11)值更改为date，然后使用Week函数，即

select WEEK(DATE(dateid)) as weeknum, game ,count(*) 
from table

DEMO

编辑： -

根据您的意见，您可以尝试使用

select concat('last ' ,(WEEK(dateid,1) -WEEK(CURDATE(),1)),' week',' ' )

DEMO

另请详细检查WEEK功能。

WEEK（）的双参数形式使您能够指定是否周从周日或周一开始，返回值是否应该是取值范围为0到53或1到53.如果mode参数为省略，使用default_week_format系统变量的值。

另见此列表供参考：

M   F.day   Range   Week 1 is the first week …
0   Sunday  0-53    with a Sunday in this year
1   Monday  0-53    with more than 3 days this year
2   Sunday  1-53    with a Sunday in this year
3   Monday  1-53    with more than 3 days this year
4   Sunday  0-53    with more than 3 days this year
5   Monday  0-53    with a Monday in this year
6   Sunday  1-53    with more than 3 days this year
7   Monday  1-53    with a Monday in this year

M = Mode
F.day = First day of week

mysql group by week，基于int dateid（yyyymmdd）

1 个答案: