Question

我有一个列表视图，其中包含2个textview和1个imageview。现在，imageview中的图像将在某些条件下设置，否则应该留空而没有图像。

问题是图像没有进入正确的行。比方说，例如，图像应显示在第3行，但在第4行显示。并且，在某些情况下，每行将具有相同的图像。

有人遇到过这种问题吗？我真的对此背后的原因毫无头绪。有谁可以指出这个问题？

private static class VilleAdapter extends BaseAdapter {
    private LayoutInflater mInflater = null;

    // private Context context = null;

    public VilleAdapter(Context context) {
        // Cache the LayoutInflate to avoid asking for a new one each time.
        mInflater = LayoutInflater.from(context);
    }

    /**
     * The number of items in the list is determined by the number of
     * speeches in our array.
     * 
     * @see android.widget.ListAdapter#getCount()
     */
    public int getCount() {
        // return BabbleMainListParse.getNumOfBabbles();
        return VilleMainListParse.getVilleCount();
    }

    /**
     * Since the data comes from an array, just returning the index is
     * sufficent to get at the data. If we were using a more complex data
     * structure, we would return whatever object represents one row in the
     * list.
     * 
     * @see android.widget.ListAdapter#getItem(int)
     */
    public Object getItem(int position) {
        return position;
    }

    /**
     * Use the array index as a unique id.
     * 
     * @see android.widget.ListAdapter#getItemId(int)
     */
    public long getItemId(int position) {
        return position;
    }

    /**
     * Make a view to hold each row.
     * 
     * @see android.widget.ListAdapter#getView(int, android.view.View,
     *      android.view.ViewGroup)
     */
    public View getView(int position, View convertView, ViewGroup parent) 
    {
        // A ViewHolder keeps references to children views to avoid
        // unneccessary calls
        // to findViewById() on each row.
        ViewHolder holder;

        // When convertView is not null, we can reuse it directly, there is
        // no need
        // to reinflate it. We only inflate a new View when the convertView
        // supplied
        // by ListView is null.
        if (convertView == null) 
        {
            convertView = mInflater.inflate(R.layout.villerow, parent,false);

            // Creates a ViewHolder and store references to the two children
            // views
            // we want to bind data to.
            holder = new ViewHolder();
            holder.txtVilleListTitle = (TextView) convertView.findViewById(R.id.txtVilleListTitle);
            holder.txtVilleDescription = (TextView) convertView.findViewById(R.id.txtVilleDescription);
            holder.imgvillepwd = (ImageView) convertView.findViewById(R.id.imgvillepwd);

            convertView.setTag(holder);
        }
        else 
        {
            // Get the ViewHolder back to get fast access to the TextView
            holder = (ViewHolder) convertView.getTag();
        }

        // Bind the data efficiently with the holder.
        holder.txtVilleListTitle.setText(VilleMainListParse.getMsgTitle(position));

        if(VilleMainListParse.getMsgDesc(position).length() > 30)
        {
            String temp = VilleMainListParse.getMsgDesc(position).substring(0, 30);
            temp = temp +".....";
            holder.txtVilleDescription.setText(temp);
        }
        else
            holder.txtVilleDescription.setText(VilleMainListParse.getMsgDesc(position));

        if(!VilleMainListParse.getPwd(position).equals(""))
        {
            if(VilleMainListParse.getUnlock(position))
            {
                holder.imgvillepwd.setBackgroundResource(R.drawable.lock);
            }   
            else if(!VilleMainListParse.getUnlock(position))
            {
                holder.imgvillepwd.setBackgroundResource(R.drawable.lock_open);
            }
        }

        return convertView;
    }

    static class ViewHolder
    {
        TextView txtVilleListTitle;
        TextView txtVilleDescription;
        ImageView imgvillepwd;
    }
}

以上代码仅适用于适配器。当点击登录按钮时，最初有一个登录屏幕，数据从互联网加载，然后这个列表视图加载了这些数据。最初正确加载此数据。

有人可以告诉我这段代码有什么问题吗？

Answer 1

当您重复使用相同的视图时，如果不应显示图像，则应清除该图像。否则，前一张图片将显示在那里。所以我建议以下修复：

if(!VilleMainListParse.getPwd(position).equals(""))
{
    if(VilleMainListParse.getUnlock(position))
    {
        holder.imgvillepwd.setBackgroundResource(R.drawable.lock);
    }   
    else if(!VilleMainListParse.getUnlock(position))
    {
        holder.imgvillepwd.setBackgroundResource(R.drawable.lock_open);
    }
}
else
    holder.imgvillepwd.setBackgroundDrawable(null);

Answer 2

您也可以考虑使用setImageResource / setImageBitmap方法而不是setBackgroundXxx。

如何在Android中的ListView内的imageview中设置图像？

2 个答案: