Question

我试图仅通过KEYS比较对象。

var obj1 = [ {"depid": "100", "depname": ""}, {"city": "abc", "state": "xyz"}, {"firstName": "John", "lastName": "Doe", "contactno": {"ph": 12345, "mob": 485428428}} ];
var obj2 = [ {"firstName": "John", "lastName": "Doe", "contactno": {"ph": 12345, "mob": 485428428}}, {"depid": "100", "depname": "role"}, {"city": "abc", "state": "xyz"} ];

例如，如果我们比较obj1中的对象{＆＃34; depid＆＃34;：＆＃34; 100＆＃34;，＆＃34; depname＆＃34;：＆＃34;＆＃34;}使用obj2 {＆＃34; depid＆＃34;：＆＃34; 100＆＃34;，＆＃34; depname＆＃34;：＆＃34; role＆＃34;}，必须返回true。由于键是相同的。我需要在obj1中设置obj2的值。

//Expected result
obj1 = [ {"depid": "100", "depname": "role"}, {"city": "abc", "state": "xyz"}, {"firstName": "John", "lastName": "Doe", "contactno": {"ph": 12345, "mob": 485428428}} ]

I have tried the solution provided in this link但仍然无法只对对象键进行比较并将值从obj2更新为obj1

Answer 1

此函数检查：对于obj1中的每个对象，它将查找obj2中的每个键。所以它检查obj2中是否存在deptid，如果是则返回true。如果

var f = function(obj1, obj2){
    console.log('Starting...', obj1.length);
    for(var i in obj1){
        var memberObj1 = obj1[i];
        var memberObj1Keys = Object.keys(memberObj1);
        console.log('Keys in each object', memberObj1Keys);
        // console.log('Checking for ', memberObj1);
        for(var j in obj2){
            var memberObj2 = obj2[j];
            console.log('Object2 ', memberObj2);
            for(var eachKey in memberObj1Keys){
                console.log('Looking for %s in obj2', memberObj1Keys[eachKey]);
                if(memberObj2[memberObj1Keys[eachKey]]){
                    console.log('Found');
                    return true;
                }
            }
        }
        console.log('======================');
    }
 return false;
}

使用该功能。

var result = f(obj1, obj2);
console.log(result);

这是您的问题的快速实施。到目前为止，我还没有尝试优化循环。

欢迎任何编辑。

基于键的对象比较

1 个答案: