Question

我有一个调用另一个程序的程序。他们从不回复对方或打电话给自己，但我收到错误回复，表明他们是。程序如下：

CREATE PROCEDURE grantPermission (perm VARCHAR(30), target VARCHAR(30), id VARCHAR(8), host VARCHAR(45), passwd VARCHAR(45))
  BEGIN 
    SET @setPermissionCmd = CONCAT('GRANT ', perm, ' ON ', target, ' TO ''', id, '''@''', host, ''' IDENTIFIED BY ''', passwd, ''';');
    PREPARE setPermissionStmt FROM @setPermissionCmd;
    EXECUTE setPermissionStmt;
    DEALLOCATE PREPARE setPermissionStmt;
    FLUSH PRIVILEGES;
  END

和

CREATE PROCEDURE grantAdmin (id VARCHAR(8), host VARCHAR(45), passwd VARCHAR(45))
  BEGIN
    CALL grantPermission('EXECUTE', 'PROCEDURE createUser', id, host, passwd);
    CALL grantPermission('EXECUTE', 'PROCEDURE grantAdmin', id, host, passwd);
    CALL grantPermission('EXECUTE', 'PROCEDURE revokeAdmin', id, host, passwd);
    CALL grantPermission('INSERT,UPDATE', 'TaskType', id, host, passwd);
    CALL grantPermission('UPDATE', 'User', id, host, passwd);
    UPDATE User SET isAdmin=1 WHERE dbUser=id;
    FLUSH PRIVILEGES;
  END

当我打电话给第二个程序时，我收到以下回复：

MariaDB [pattsdb]> CALL grantAdmin('patts', '%', 'patts');
ERROR 1456 (HY000): Recursive limit 0 (as set by the max_sp_recursion_depth variable) was exceeded for routine grantAdmin

为什么它认为我的程序是递归的？只是因为定义文本中提到了名称？

Answer 1

将其添加到存储过程的开头：

SET max_sp_recursion_depth=255;

非递归过程中超出递归限制

1 个答案: