我已经创建了一个包含d3.nest()
个对象的折线图,但我需要每个段的填充颜色基于另一个变量。我想我可以根据数据文件中的gradient
来做,但实际上需要在段的距离上计算。现在,当它应该是
if gradient < -10
color = red
if gradient < -5
color = green
if gradient < 0
color = white
if gradient < 5
color = yellow
if gradient < 10
color = black
else
color = blue
这里是Plunk
<!DOCTYPE html>
<meta charset="utf-8">
<style>
body {
font: 12px Arial;
}
text.shadow {
stroke: #fff;
stroke-width: 2.5px;
opacity: 0.9;
}
path {
stroke: steelblue;
stroke-width: 2;
fill: none;
}
.axis path,
.axis line {
fill: none;
stroke: grey;
stroke-width: 1;
shape-rendering: crispEdges;
}
.grid .tick {
stroke: lightgrey;
stroke-opacity: 0.7;
shape-rendering: crispEdges;
}
.grid path {
stroke-width: 0;
}
.area {
stroke-width: 0;
}
</style>
<body>
<script src="http://d3js.org/d3.v3.min.js"></script>
<script>
var margin = {top: 30, right: 20, bottom: 35, left: 50},
width = 600 - margin.left - margin.right,
height = 270 - margin.top - margin.bottom;
var color = d3.scale.ordinal()
.domain([-10,-5,0,5,10])
.range(['red','green','white','yellow','black','blue']);
var x = d3.scale.linear().range([0, width]);
var y = d3.scale.linear().range([height, 0]);
var xAxis = d3.svg.axis()
.scale(x)
.orient("bottom")
.ticks(5);
var yAxis = d3.svg.axis()
.scale(y)
.orient("left")
.ticks(5);
var area = d3.svg.area()
.x(function(d) { return x(d.distance); })
.y0(height)
.y1(function(d) { return y(d.elevation); });
var valueline = d3.svg.line()
.x(function(d) { return x(d.distance); })
.y(function(d) { return y(d.elevation); });
var svg = d3.select("body")
.append("svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform",
"translate(" + margin.left + "," + margin.top + ")");
// function for the x grid lines
function make_x_axis() {
return d3.svg.axis()
.scale(x)
.orient("bottom")
.ticks(5)
}
// function for the y grid lines
function make_y_axis() {
return d3.svg.axis()
.scale(y)
.orient("left")
.ticks(5)
}
// Get the data
d3.csv("data.csv", function(error, data) {
data.forEach(function(d) {
d.distance = +d.distance;
d.elevation = +d.elevation;
d.gradient = +d.gradient;
});
var dataGroup = d3.nest()
.key(function(d) {
return d.grade;
})
.entries(data);
dataGroup.forEach(function(group, i) {
if(i < dataGroup.length - 1) {
group.values.push(dataGroup[i+1].values[0])
}
})
// Scale the range of the data
x.domain(d3.extent(data, function(d) { return d.distance; }));
y.domain([0, d3.max(data, function(d) { return d.elevation; })]);
dataGroup.forEach(function(d, i){
svg.append("path")
.datum(d.values)
.attr("class", "area")
.attr("d", area);
});
svg.selectAll(".area")
.style("fill", function(d) { return color(d.gradient); });
// Draw the x Grid lines
svg.append("g")
.attr("class", "grid")
.attr("transform", "translate(0," + height + ")")
.call(make_x_axis()
.tickSize(-height, 0, 0)
.tickFormat("")
)
// Draw the y Grid lines
svg.append("g")
.attr("class", "grid")
.call(make_y_axis()
.tickSize(-width, 0, 0)
.tickFormat("")
)
// Add the valueline path.
svg.append("path")
.attr("d", valueline(data));
// Add the X Axis
svg.append("g")
.attr("class", "x axis")
.attr("transform", "translate(0," + height + ")")
.call(xAxis);
// Add the Y Axis
svg.append("g")
.attr("class", "y axis")
.call(yAxis);
// Add the text label for the X axis
svg.append("text")
.attr("transform",
"translate(" + (width/2) + " ," +
(height+margin.bottom) + ")")
.style("text-anchor", "middle")
.text("Distance");
// Add the text label for the Y axis
svg.append("text")
.attr("transform", "rotate(-90)")
.attr("y", 6)
.attr("x", margin.top - (height / 2))
.attr("dy", ".71em")
.style("text-anchor", "end")
.text("");
// Add the title
svg.append("text")
.attr("x", (width / 2))
.attr("y", 0 - (margin.top / 2))
.attr("text-anchor", "middle")
.style("font-size", "16px")
.style("text-decoration", "underline")
.text("Elevation Graph");
});
</script>
</body>
答案 0 :(得分:1)
问题在于这个电话:
svg.selectAll(".area")
.style("fill", function(d) { return color(d.gradient); });
这里,“d”是长度为1或2的对象数组,具体取决于索引。我不知道你希望使用哪个对象的渐变,但是在不理解你的数据的情况下我的天真解决方案是使用d [0]。这是Plunk。