Question

我正在尝试制作一个棋盘格。我有这个代码来制作一个棋盘 - 它可以工作，但行不匹配。如何让每一行从头开始，例如向后退150？我尝试了一行向后150，然后第二回向120.

import turtle
turtle.speed(0)

def go_to_start():
    turtle.pu()
    turtle.backward(150)
    turtle.left(90)
    turtle.forward(250)
    turtle.right(90)
    turtle.pd()

def colour():
    turtle.fillcolor('black')
    for j in range(5):
        turtle.begin_fill()
    for i in range (4):
        turtle.forward(30)
        turtle.right(90)
    turtle.end_fill()
    turtle.pu()
    turtle.forward(60)
    turtle.pd()



def first_row():
    turtle.pu()
    turtle.backward(180)
    turtle.right(90)
    turtle.forward(30)
    turtle.right(270)
    turtle.pd()



def second_row():
    turtle.pu()
    turtle.backward(150)
    turtle.right(90)
    turtle.right(270)
    turtle.pd()


go_to_start()


for j in range (5):
    for i in range (5):
        colour()
    second_row()
    first_row()

Answer 1

对于表格的每一行，这将返回相同的距离，这是不正确的。您需要实现一些逻辑以返回每行的正确数量。例如，您可以使用：

替换first_row，second_row和for循环

def reset():
    turtle.pu()
    turtle.backward(300)
    turtle.right(90)
    turtle.forward(30)
    turtle.right(270)
    turtle.pd()


for j in range (5):
    for i in range (5):
        colour()
    #if the row is even, then go forward 30
    if j %2 == 0:
        turtle.forward(30)
    #if the row is odd, then go backward 30
    else:
        turtle.backward(30)
    reset()

Answer 2

我提出了一些建议，使您的程序更简单，更快捷。首先，棋盘是盖章的绝佳机会，而不是 draw 。其次，不要再从左到右思考，而是双向思考：

import turtle

CURSOR_SIZE = 20
SQUARE_SIZE = 30

turtle.shape('square')
turtle.shapesize(SQUARE_SIZE / CURSOR_SIZE)
turtle.penup()

distance = 2 * SQUARE_SIZE

for j in range(8):
    for _ in range(4):
        turtle.stamp()
        turtle.forward(distance)

    # if row is odd, go forward one square else go backward one square
    turtle.forward(SQUARE_SIZE if j % 2 else -SQUARE_SIZE)

    distance = -distance

    turtle.sety(turtle.ycor() - SQUARE_SIZE)

turtle.hideturtle()

turtle.done()

Python龟棋盘每行从右边开始30像素

2 个答案: