使用多个调度程序servlet / web上下文与spring boot

时间:2015-03-17 10:18:22

标签: java spring spring-mvc servlets spring-boot

我创建了一个带有父上下文(服务)和子上下文(spring-webmvc控制器)的spring启动应用程序:

@Configuration
public class MainApiApplication {

    public static void main(String[] args) {
        new SpringApplicationBuilder()
                .parent(Services.class)
                .child(ApiOne.class, MainApiApplication.class)
                .run(args);
    }

    @Bean
    public EmbeddedServletContainerFactory servletContainer() {
        return new TomcatEmbeddedServletContainerFactory();
    }

}

现在我想为我的ApiTwo.class配置添加另一个客户端上下文(和DispatcherServlet)。我想我必须做两件事:

  1. 将servletContainer(因此MainApiApplication.class配置)移出子上下文并
  2. 添加路径映射/ one / - > ApiOne.class和/ two / ApiTwo.class
  3. 春季引导方式是什么?

2 个答案:

答案 0 :(得分:26)

正如@josh-ghiloni已经说过的那样,您需要为要创建的每个隔离的Web上下文注册ServletRegistrationBean。 您需要从xml或java配置类创建应用程序上下文。您可以使用@Import@ComponentScan注释将共享服务添加到父上下文。这是一个例子:

import org.springframework.boot.SpringApplication;
import org.springframework.boot.context.embedded.ServletRegistrationBean;
import org.springframework.context.annotation.Bean;
import org.springframework.web.context.support.AnnotationConfigWebApplicationContext;
import org.springframework.web.context.support.XmlWebApplicationContext;
import org.springframework.web.servlet.DispatcherServlet;


//@ComponentScan({"..."})
//@Import({})
public class Starter {

    public static void main(String[] args) throws Exception {
        SpringApplication.run(Starter.class, args);
    }

    @Bean
    public ServletRegistrationBean apiV1() {
        DispatcherServlet dispatcherServlet = new DispatcherServlet();

        XmlWebApplicationContext applicationContext = new XmlWebApplicationContext();
        applicationContext.setConfigLocation("classpath:/META-INF/spring/webmvc-context.xml");
        dispatcherServlet.setApplicationContext(applicationContext);

        ServletRegistrationBean servletRegistrationBean = new ServletRegistrationBean(dispatcherServlet, "/api/1/*");
        servletRegistrationBean.setName("api-v1");

        return servletRegistrationBean;
    }

    @Bean
    public ServletRegistrationBean apiV2() {
        DispatcherServlet dispatcherServlet = new DispatcherServlet();

        AnnotationConfigWebApplicationContext applicationContext = new AnnotationConfigWebApplicationContext();
        applicationContext.register(ResourceConfig.class);
        dispatcherServlet.setApplicationContext(applicationContext);

        ServletRegistrationBean servletRegistrationBean = new ServletRegistrationBean(dispatcherServlet, "/api/2/*");
        servletRegistrationBean.setName("api-v2");
        return servletRegistrationBean;
    }
}

答案 1 :(得分:8)

创建一个声明servlet及其映射的ServletRegistrationBean。您可能还希望从调用的自动配置中排除DispatcherServletAutoConfiguration,因为它会在DispatcherServlet注册/并覆盖您的<{p}}

编辑尽管下面的评论说你可能不需要这个,但除非你需要在不同的端口上运行你的API(并且听起来不像你这样做),Dave Syer,其中一位作者Spring Boot回答了一个非常相似的问题:Configure multiple servletcontainers/servlets with spring boot