实现不可重复的<t>没有代码重复的正确方法</t>

Question

目前我已经像下面那样实现了它，但我不喜欢它因为GetEnumerator中的代码重复，我该如何删除重复...

public class EodSettlementRequestStubData : IEnumerable<SettlementRequest>
{

    public SettlementRequest UnapprovedFlows;
    public SettlementRequest UnapprovedRecovery;
    public SettlementRequest UnverifiedFlows;
    public SettlementRequest UnverifiedRecovery;

    IEnumerator<SettlementRequest> IEnumerable<SettlementRequest>.GetEnumerator()
    {
        yield return UnapprovedFlows;
        yield return UnapprovedRecovery;
        yield return UnverifiedFlows;
        yield return UnverifiedRecovery;
    }

    public IEnumerator GetEnumerator()
    {
        yield return UnapprovedFlows;
        yield return UnapprovedRecovery;
        yield return UnverifiedFlows;
        yield return UnverifiedRecovery;
    }
}

我希望能够单独访问它，以及IEnumerable来做一些linq的东西......

我可以创建一个列表以避免代码重复，但我觉得应该有更好的方法来处理这个......

Answer 1

让非泛型版本调用泛型版本（将explictit接口版本设置为非泛型IEnumerable而不是通用版IEnumerable<T>更为“正常”）

public class EodSettlementRequestStubData : IEnumerable<SettlementRequest>
{

    public SettlementRequest UnapprovedFlows;
    public SettlementRequest UnapprovedRecovery;
    public SettlementRequest UnverifiedFlows;
    public SettlementRequest UnverifiedRecovery;

    public IEnumerator<SettlementRequest> GetEnumerator()
    {
        yield return UnapprovedFlows;
        yield return UnapprovedRecovery;
        yield return UnverifiedFlows;
        yield return UnverifiedRecovery;
    }

    IEnumerator IEnumerable.GetEnumerator()
    {
        //This is calling "IEnumerator<SettlementRequest> GetEnumerator()"
        return GetEnumerator();
    }
}