Question

我每次进入for循环时都会发生奇怪的崩溃，将每个位置初始化为undefined。任何人都可以阐明为什么会这样吗？＃包括＃包括＃包括使用namespace std;

class MyPhoneBook
{
public:
    MyPhoneBook(int, string, string, string, string);
    MyPhoneBook();
    ~MyPhoneBook();

    void initialise(int, int, string, string, string, string);
    bool search(string&, int);
    bool find_free_pos();
    void add(); 
    void remove(); 
    void display(int);

    friend istream& operator >> (istream& in, MyPhoneBook& ph);
    friend ostream& operator << (ostream& out, MyPhoneBook& ph);

    private:
    int *recordid; 
    int *status; // -1 is no longer at this number, 0 is blocked, 1 is not blocked, 2 is free
    string *name, *areacode, *number, *group;
    };

    int main(int argc, char** argv) 
    {
        cout << "test 1" << endl;
        MyPhoneBook *myphbk;                    // pointer that will point to an object of a MyPhoneBook class
        myphbk = new MyPhoneBook[100];          // now its using dynamic memory

        cout << "test 2" << endl;       //just for testing

        int pos = 0;
        for(pos = 0; pos < 100; pos++)          // initializing everything to undefined, and position to free (position is the second parameter sended in)
        {
            myphbk[pos].initialise( (pos+1) , 2 , "Undefined" , "Undefined" , "Undefined" , "Undefined");
        }

        cout << "test 3" << endl;       //just for testing
    }

return 0;

void MyPhoneBook::initialise(int recordid_,int status_, string name_, string     areacode_, string number_, string group_)
{
   //now assign them to private member variables
   *recordid = recordid_;
   *status = status_;
   *name = name_;
   *areacode = areacode_;
   *number = number_;
   *group = group_;
   //end of assigning
}

有没有人知道为什么我的程序无法到达cout＆lt;＆lt; “测试3”＆lt;＆lt; endl部分程序没有崩溃？

Answer 1

由于你没有粘贴MyPhoneBook的构造函数，我只能猜测，但问题可能是行

*recordid = recordid_;
*status = status_;

如果您没有在构造函数中为recordid和status分配有效地址，例如由

recordid = new int;
status = new int;

您可能希望将这些成员变量声明为简单int。

C ++程序崩溃（与动态内存有关）

1 个答案: