我试图使用数组列表制作电话簿，但我没有得到正确的输出，这是我的代码，谢谢你对此的任何帮助，我现在得到的输出只是一个零时我问大小，似乎没有添加任何人，这可能是问题所在
import java.util.ArrayList;
public class Phonebook implements Directory
{
private ArrayList<Person> book;
public Phonebook ()
{
book = new ArrayList<Person>();
}
/**
* will return the number of entries currently entered in
* the <code>Directory</code>.
* @return - the number of valid entries in the <code>Directory</code>.
**/
public int size()
{
return book.size();
}
/**
* will display the entries currently entered in the <code>Directory</code>.
**/
public void listAll()
{
for(int i = 0; i < book.size(); i++)
{
System.out.println(book.get(i));
}
}
/**
* will add a new record to the <code>Directory</code> in alphabetical order
* if the name is not a duplicate entry. Otherwise no changes will be made.
* @param name - name of individual to be added to the <code>Directory</code>.
* @param number - phone number of the individual to be added.
* @return - true if the entry was added successfully, otherwise false.
**/
public boolean addPerson(String name, String number)
{
Person x = new Person (name, number);
if (checkPerson(name) == -1)
return false;
int index = 0;
while(index < book.size())
{
if((x.getName().compareTo((book.get(index)).getName())) < 0)
{
book.add(x);
return true;
}
index++;
}
return false;
}
public int checkPerson(String name)
{
int lo = 0;
int hi = book.size() - 1;
while(lo <= hi)
{
int half = (lo + hi) / 2;
if(name.equals(book.get(half).getName()))
return half;
if(name.compareTo(book.get(half).getName()) < 0){
hi = half - 1;}
else lo = half + 1;
}
return -1;
}
/**
* will remove an entry from the <code>Directory</code> if the name parameter
* is currently in the <code>Directory</code>. Otherwise no changes
* will be made.
* @param name - individual to be removed from the <code>Directory</code>.
* @return - true if the entry was successfully removed, otherwise false.
**/
public boolean removePerson(String name)
{
if (checkPerson(name) == -1)
return false;
book.remove(checkPerson(name));
return true;
}
/**
* will search the <code>Directory</code> to find out if the name passed in
* is currently in the <code>Directory</code>. If so, it will return the
* phone number associated with this person. Otherwise it will return null.
* @param name - name of individual to look up in the <code>Directory</code>.
* @return - the phone number if the name was found, otherwise null.
**/
public String lookUp(String name)
{
Person n = new Person (name, "999-9999");
int local = checkPerson(n.getName());
if(local == -1)
return null;
return book.get(local).getNumber();
}
/**
* will search the <code>Directory</code> to find out if the phone number
* is currently in the <code>Directory</code>. If so, it will return the
* name associated with this number. Otherwise it will return null.
* @param number - name of individual to look up in the <code>Directory</code>.
* @return - the name of the person if the number was found, otherwise null.
**/
public String lookUpNum(String number)
{
for(int i = 0; i <book.size(); i++)
{
if(number.equals(book.get(i).getNumber()))
return book.get(i).getName();
}
return null;
}
}
/ ** * Person 类是一个容纳类的容器类 *个人的姓名和电话号码。有方法 *访问名称和号码，并修改名称和号码。 *每个名称都存储在＆＃34; Last，First＆＃34;形式，以方便搜索 *和人员分类。使用私有帮助方法 *确保姓名输入＆＃34; First Last＆＃34;表格转换为 *正确的格式。 * /
public class Person implements Comparable<Person>
{
private String first;
private String last;
private String name; // Last, First
private String number;
/**
* explicit constructor, will store the first and last
* names, as well as the entire name in Last, First order
*
* @param na is the name of the individual
* @param nu is the phone number of the individual
*/
public Person(String na, String nu)
{
convert(na);
number = nu;
}
/**
* copy constructor, will make an exact copy of the parameter
*
* @param per is the <B>Person</B> to be duplicated
*/
public Person(Person per)
{
first = per.first;
last = per.last;
name = per.name;
number = per.number;
}
/**
* accessor method to return the name of <B>this Person</B>
*
* @return the name of the individual in Last, First order
*/
public String getName()
{
return name;
}
/**
* accessor method to return the phone number of <B>this Person</B>
*
* @return the phone number of the individual
*/
public String getNumber()
{
return number;
}
/**
* modifier method to set a new name for <B>this Person</B>
* The helper method convert() is called to handle the details
*
* @param the new name for the individual
*/
public void setName(String na)
{
convert(na);
}
/**
* modifier method to set a new phone number <B>this Person</B>
* just in case somebody needs to enter witness protection
*
* @param the new phone number for the individual
*/
public void setNumber(String num)
{
number = num;
}
/**
* accessor method that implements the <B>Comparable interface</B>
* based on the name field for <B>this Person</B>
* will return a positive number if <B>this</B> is greater than oth
* zero if <B>this</B> is equal to oth
* and a negative number if <B>this</B> is less than oth
*
* @return negative, zero, or positive int as per Comparable interface
*/
public int compareTo(Person oth)
{
return name.toUpperCase().compareTo(oth.name.toUpperCase());
}
/**
* accessor method to test if the instance data for <B>this Person</B>
* is equal to the instance data for oth
*
* @return true if names and numbers match, false otherwise
*/
public boolean equals(Person oth)
{
return name.toUpperCase().equals(oth.name.toUpperCase()) && number.equals(oth.number);
}
private void convert(String na)
{
if(na.indexOf(" ") == -1)
{
last = na;
first = null;
name = na;
}
else if(na.indexOf(",") != -1)
{
name = na;
first = na.substring(na.indexOf(",") + 2);
last = na.substring(na.indexOf(","));
}
else
{
first = na.substring(0, na.indexOf(" "));
last = na.substring(na.indexOf(" ") + 1);
name = last + ", " + first;
}
}
/**
* accessor method to return the instance data of <B>this Person</B>
* in a formatted String (24 character name field, followed by the number)
*
* @return name in Last, First order followed by the phone number
*/
public String toString()
{
String local = name;
if(name.length() < 8)
local += "\t";
if(name.length() < 16)
local += "\t";
local += "\t" + number;
return local;
}
}
public class client
{
public static void main(String[] args)
{
Phonebook nickBook = new Phonebook();
nickBook.addPerson("name lastname", "321-3256");
System.out.println();
nickBook.listAll();
System.out.println(nickBook.size());
}
}
答案 0 :(得分：1)
如果列表为空，则您的addPerson方法不会添加Person，因为while (0 < 0)将为false，并且不会输入循环：
int index = 0;
while(index < book.size())
{
if((x.getName().compareTo((book.get(index)).getName())) < 0)
{
book.add(x);
return true;
}
index++;
}
除了这个问题，book.add(x);将始终将新的Person添加到列表的末尾，这不是您想要的。您应该使用book.add(index,x)，假设index是您希望添加新Person的位置。
最后，如果新的Person没有被添加到while循环中，这意味着这个Person应该是List中的最后一个Person，所以你必须在循环之后将它添加到List的末尾。 / p>
可能的实施：
public boolean addPerson(String name, String number)
{
Person x = new Person (name, number);
if (checkPerson(name) == -1)
return false;
int index = 0;
while(index < book.size())
{
if((x.getName().compareTo((book.get(index)).getName())) < 0)
{
book.add(index,x);
return true;
}
index++;
}
book.add(x); // this handles both the case of an empty List and the
// case in which the new Person should be the last Person
// on the list
return true;
}
答案 1 :(得分：1)
您的函数checkPerson错误。 book.size()在开头为0，hi结果为-1，这意味着它不会进入循环。除此之外，请考虑一下half变量。如果您使用此变量作为列表查询的索引，则可能会导致另一个数字而不是整数。
public int checkPerson(String name)
{
int lo = 0;
int hi = book.size() -1;
while(lo <= hi)
{
int half = (lo + hi) / 2;
if(name.equals(book.get(half).getName()))
return half;
if(name.compareTo(book.get(half).getName()) < 0){
hi = half - 1;}
else lo = half + 1;
}
return -1;
}