Question

我想在我的网站上创建一个html / javascript表单。随着形式我喜欢发送Android和iOS设备的推送通知。

登录http请求正常工作：

httpRequest.open('POST','https://api.cloud.appcelerator.com/v1/users/login.json?key=xxxAPKEYxxx&login=xxxEMAILxxx&password=xxxPASSWORDxxx');
    httpRequest.send();     
    httpRequest.onload = function(){             
var data = JSON.parse(this.responseText);
var sessionID = data.meta.session_id;
sendPush();
}

回复：{＆＃34; meta＆＃34;：{＆＃34; code＆＃34;：200，＆＃34; status＆＃34;：＆＃34; ok＆＃34;，＆＃34; method_name＆＃34;：＆＃34; loginUser＆＃34; ....因此登录成功。但是当我调用sendPush函数时，我得到一个响应错误：响应错误：＆＃34;状态＆＃34;：＆＃34;失败＆＃34 ;, ＆＃34;代码＆＃34;：400，＆＃34; message＆＃34;：＆＃34;无法验证用户＆＃34;。

function sendPush(){  
    httpRequest.open('POST','https://api.cloud.appcelerator.com/v1/push_notification/notify.json?key=xxxAPPKEYxxx&channel=xxxCHANNELxxx&payload=test');
    httpRequest.send();
    httpRequest.onload = function()
 {
   console.log(this.responseText);
 };
}

Answer 1

function sendPush(){  
    var BASEURL = 'https://api.cloud.appcelerator.com/v1/'
    httpRequest.open('POST', BASEURL + 'push_notification/notify.json?key=APPKE');
    httpRequest.send({
       channel : "xxxCHANNELxxx",
       payload : "test"
    });
    httpRequest.onload = function() {
       console.log(this.responseText);
    };
}

登录后无法使用ACS REST API发送推送通知

1 个答案: