Question

#include <boost/bind.hpp>
#include <iostream>

using namespace std;
using boost::bind;

class A {
public:
    void print(string &s) {
        cout << s.c_str() << endl;
    }
};


typedef void (*callback)();

class B {
public:
    void set_callback(callback cb) {
        m_cb = cb;
    }

    void do_callback() {
        m_cb();
    }

private:
    callback m_cb;
};

void main() {
    A a;
    B b;
    string s("message");
    b.set_callback(bind(A::print, &a, s));
    b.do_callback();

}

所以我要做的是在激活b回调时将A流“消息”的打印方法设置为cout。我从msvc10得到了意外数量的参数错误。我确定这是超级noob基本的，我很抱歉。

Answer 1

将typedef void (*callback)();替换为typedef boost::function<void()> callback;

绑定函数不会生成普通函数，因此您不能将其存储在常规函数指针中。但是，boost::function能够处理任何，只要它可以使用正确的签名进行调用，这就是您想要的。它将使用函数指针或使用bind创建的仿函数。

在对代码进行一些更正之后，我想出了这个：

#include <boost/bind.hpp>
#include <boost/function.hpp>
#include <iostream>

// i prefer explicit namespaces, but that's a matter of preference

class A {
public:
    // prefer const refs to regular refs unless you need to modify the argument!
    void print(const std::string &s) {
        // no need for .c_str() here, cout knows how to output a std::string just fine :-)
        std::cout << s << std::endl;
    }
};


// holds any arity 0 callable "thing" which returns void
typedef boost::function<void()> callback;

class B {
public:
    void set_callback(callback cb) {
        m_cb = cb;
    }

    void do_callback() {
        m_cb();
    }

private:
    callback m_cb;
};

void regular_function() {
    std::cout << "regular!" << std::endl;
}

// the return type for main is int, never anything else
// however, in c++, you may omit the "return 0;" from main (and only main)
// which will have the same effect as if you had a "return 0;" as the last line
// of main
int main() {
    A a;
    B b;
    std::string s("message");

    // you forget the "&" here before A::print!
    b.set_callback(boost::bind(&A::print, &a, s));
    b.do_callback();

    // this will work for regular function pointers too, yay!
    b.set_callback(regular_function);
    b.do_callback();

}

Noob boost :: bind成员函数回调问题

1 个答案: