我正在尝试创建一个刽子手游戏。当字母与变量“word”中的字母匹配时,我需要用变量“letter”中的字母替换变量“underscore”中的下划线。这样做的任何方式?
for( i = 0; i < word.length; i++ ) {
if (word[i] === letter) {
underscore = underscore.replace(underscore.charAt(i*2), letter);
}
}
上面是我的代码的特定部分,我现在试图替换它,但它只会在信件/开头之后替换下一个下划线,无论我做什么。如果您需要有关其工作原理的更多详细信息,请参阅下面的完整代码。
提前致谢。
/* Hangman Game CSS File */
body
{
background-color: #1B264F;
}
#main {
background-color: #5386E4;
height: 97vh;
width: 95vw;
vertical-align: middle;
}
canvas {
padding-left: 0;
padding-right: 0;
margin-left: auto;
margin-right: auto;
display: block;
margin-top: auto;
margin-bottom: auto;
}
<!DOCTYPE html>
<html>
<head>
<title>Hangman by Lachlan Teale</title>
<meta name="description" content="Lachlan Teale's Hangman Game 2015">
<meta name="keywords" content="hangman, lachlan, teale, Javascript">
<meta charset="UTF-8">
<meta name="author" content="Lachlan Teale">
<link rel="stylesheet" type="text/css" href="style.css">
</head>
<body>
<canvas id="main" width="1920" height="1080" style="border:1px solid #d3d3d3;"></canvas>
<script type="text/javascript">
//setting variables
var canvas = document.getElementById('main');
var context = canvas.getContext('2d');
var underscore = "";
var letter;
var complete = false;
//list of words
var wordList = ["apple", "peach", "pear", "mango", "banana", "paper", "pens", "laptop", "desk", "chair", "star", "sky", "moon", "sun", "planets"];
//picking a random word from the list
var word = wordList[Math.floor(Math.random() * wordList.length)];
//print out the underscores for the number of letters
for (i = 0; i < word.length; i++) {
var underscore = underscore + "_ ";
}
context.font = '50pt Calibri';
context.textAlign = 'center';
context.fillStyle = '#E2E2E3';
context.fillText(underscore, canvas.width * 0.5, canvas.height * 0.70);
//correct letter text
context.font = 'bold 30pt Calibri';
context.textAlign = 'center';
context.fillStyle = '#E2E2E3';
context.text
context.fillText("Correct Letters", canvas.width * 0.08, canvas.height * 0.05);
//Wrong Letter text
context.font = 'bold 30pt Calibri';
context.textAlign = 'center';
context.fillStyle = '#E2E2E3';
context.text
context.fillText("Wrong Letters", canvas.width - (canvas.width * 0.08), canvas.height * 0.05);
//checking which button is pressed
window.addEventListener('keydown', function(event) {
if ( event.keyCode >= 65 && event.keyCode <= 90 ) {
context.clearRect(0, canvas.height * 0.80, canvas.width, canvas.height);
letter = String.fromCharCode( event.keyCode ).toLowerCase();
context.font = '50pt Calibri';
context.textAlign = 'center';
context.fillStyle = '#E2E2E3';
context.fillText(letter, canvas.width * 0.5, canvas.height * 0.85);
}
});
//checking if back key is pressed
document.addEventListener('keydown', function(event) {
if ( event.keyCode == 8 ) {
context.clearRect(0, canvas.height * 0.80, canvas.width, canvas.height);
}
});
//checking if enter is pressed
document.addEventListener('keydown', function(event) {
if( event.keyCode == 13 ) {
//checking if letter is in the word
alert(word);
for( i = 0; i < word.length; i++ ) {
if (word[i] === letter) {
underscore = underscore.replace(underscore.charAt(i*2), letter);
}
}
context.clearRect(canvas.width * 0.4, canvas.height * 0.3, canvas.width *0.7, canvas.height * 70);
context.font = '50pt Calibri';
context.textAlign = 'center';
context.fillStyle = '#E2E2E3';
context.fillText(underscore, canvas.width * 0.5, canvas.height * 0.70);
alert(underscore);
}
});
</script>
</body>
</html>
答案 0 :(得分:0)
由于字符串underscore
中的所有字符均为“_”,因此当您运行underscore.replace(underscore.charAt(i*2), letter);
时
它查看i*2
处字符的字符串,然后用letter
替换该字符的第一个实例(您可以在此处找到此文档:http://www.w3schools.com/jsref/jsref_replace.asp)。
您可能想要做的是定义如下函数:
function replaceAt(str,index,chr) {
if(index > str.length-1) return str;
return str.substr(0,index) + chr + str.substr(index+1);
}
并使用该函数代替replace()
您可以声明该功能,然后在之前调用.replace()
之前调用它。当您调用它时,只需将str
替换为字符串(underscore
),将index
替换为您想要新字母的索引,将ltr
替换为您想要的新字母(letter
)。