“'字段列表中的未知列'当列存在时

时间:2015-03-16 08:12:45

标签: php mysql mysqli error-handling

我创建了一个数据库,它包含:

desc users;
+--------------+--------------+------+-----+---------+----------------+
| Field        | Type         | Null | Key | Default | Extra          |
+--------------+--------------+------+-----+---------+----------------+
| UserID       | int(25)      | NO   | PRI | NULL    | auto_increment |
| Username     | varchar(65)  | YES  |     | NULL    |                |
| Fname        | varchar(65)  | YES  |     | NULL    |                |
| Lname        | varchar(65)  | YES  |     | NULL    |                |
| Password     | varchar(32)  | YES  |     | NULL    |                |
| Password1    | varchar(32)  | YES  |     | NULL    |                |
| EmailAddress | varchar(255) | YES  |     | NULL    |                |
+--------------+--------------+------+-----+---------+----------------+
7 rows in set (0.00 sec)

但是,当我运行此代码时

if($email_exists == false && $Password == $Password1)
            {
                $sql="INSERT INTO users(u_Username, u_Fname, u_Lname, u_EmailAddress, u_Password)
                VALUES('$_POST[$Username]', '$_POST[$Fname]', '$_POST[$Lname]', '$_POST[$EmailAddress]', '$_POST[$Password]')";
                echo "<pre>"; print_r($sql); exit;
                if(!mysqli_query($link, $sql))
                {
                    #$query = mysqli_query($myConnection, $sqlCommand);
                    #die (mysqli_error($myConnection));
                    die('Error: ' . mysqli_error($link));               
                }
                header("location: login.php");
            }

我收到此错误:

INSERT INTO users(u_Username, u_Fname, u_Lname, u_EmailAddress, u_Password)
                VALUES('', '', '', '', '')

这里有什么错误?我正在使用php和mysqli。我是新手,但我试图让我的register.php文件接受并添加到我的数据库。

编辑这里是完整的代码

<?php 
session_start();
require_once('connect.php');
require_once "utils.php";

if(isset($_POST['submit']))
{
    //CHECK EMPTY FORM DATA and SANITIZE
    if(!empty($_POST['Username'])&&
       !empty($_POST['Fname'])&& 
       !empty($_POST['Lname'])&& 
       !empty($_POST['EmailAddress'])&& 
       !empty($_POST['Password'])&& 
       !empty($_POST['Password1']))
    {
        $Username = mysqli_real_escape_string($link,htmlentities($_POST['Username']));
        $Fname = mysqli_real_escape_string($link,htmlentities($_POST['Fname']));
        $Lname = mysqli_real_escape_string($link,htmlentities($_POST['Lname']));
        $Password = mysqli_real_escape_string($link,htmlentities($_POST['Password']));
        $Password1 = mysqli_real_escape_string($link,htmlentities($_POST['Password1']));
        $EmailAddress = mysqli_real_escape_string($link,htmlentities($_POST['EmailAddress']));
    }

    else { header("Location: register.php");exit(); }

        if(isset($EmailAddress) && !empty($EmailAddress) &&
           isset($Password) && !empty($Password))
        {
            $email_exists = false;

            $sql="SELECT * FROM users WHERE EmailAddress='$EmailAddress'";

            if($result = mysqli_query($link, $sql))
            {
                while($record = mysqli_fetch_row($result))
                {
                    if($record = $EmailAddress)
                    {
                        $email_exists = true;
                    }

                    if($email_exists = true)
                    {
                        echo "<div id='reg_error1'>* The Email Used Already Exists! <br></div>";
                    }
                }
            }

            if($Password != $Password1)
            {
                echo "<div id='reg_error2'>* Your Password Does Not Match!<br></div>";
            }

            if($email_exists == false && $Password == $Password1)
            {
                $sql="INSERT INTO users(Username, Fname, Lname, EmailAddress, Password)
                VALUES('{$_POST['$Username']}', '{$_POST['$Fname']}', '{$_POST['$Lname']}', '{$_POST['$EmailAddress']}', '{$_POST['$Password']}')";
                echo "<pre>"; print_r($sql); exit;
                if(!mysqli_query($link, $sql))
                {
                    #$query = mysqli_query($myConnection, $sqlCommand);
                    #die (mysqli_error($myConnection));
                    die('Error: ' . mysqli_error($link));               
                }
                header("location: login.php");
            }
            echo "<hr>";
        }
}

3 个答案:

答案 0 :(得分:1)

$sql="INSERT INTO users(Username, Fname, Lname, EmailAddress, Password)
                VALUES('{$_POST['$Username']}', '{$_POST['$Fname']}', '{$_POST['$Lname']}', '{$_POST['$EmailAddress']}', '{$_POST['$Password']}')";

???

您已经将POST变量提取到那些本地变量中,那么为什么要尝试将它们用作post数组的索引参数?

 $sql="INSERT INTO users(Username, Fname, Lname, EmailAddress, Password)
                VALUES('{$Username'}', '{$Fname}', '{'$Lname}', '{'$EmailAddress'}', '{$Password}')";

如果我错误地编辑了你的代码,就像在错误的位置引用的那样,那就是因为我不会像以前那样编写查询。 PDO和准备好的语句或存储过程就是我一直在使用sonce 2003而且我相信那些不这样做的人只是在惹麻烦。

答案 1 :(得分:0)

您已将$ _POST值存储在变量中,如

$Username = mysqli_real_escape_string($link,htmlentities($_POST['Username']));

所以在查询中使用这些变量。

INSERT INTO users(Username, Fname, Lname, EmailAddress, Password)
            VALUES('$Username'', '$Fname', '$Lname', '$EmailAddress', '$Password')

答案 2 :(得分:0)

你可以在处理像这样的小表时插入它。这是一个简短的手,但运作良好。

$sql="INSERT  INTO users VALUES('', '$_POST[Username]', '$_POST[Fname]', '$_POST[Lname]', '$_POST[EmailAddress]', '$_POST[Password]')"; 
  

&#39;&#39; ...未指定,因为它是自动生成的。   在表格中,因为ID是主键,我希望你把它放在自动增量上,我只是把它留空了一个值或&#39;&#39; ...没有指定,因为它是&#39; s自动生成。

此外,我不鼓励您直接从用户插入值而不进行任何服务器端验证。