对于我的移动应用程序,我正在使用Web服务从MySQL数据库中获取图像和所有记录,就像Instagram一样。
但SELECT DISTINCT花了7到8秒钟。我能做些什么来减少时间?
SELECT distinct count(*) as totalrecord ,p.description,p.photo_id ,p.user_id,p.imagepath1 ,p.friends, p.is_report_photo,
p.imagepath2,p.imagepath3,p.imagepath4,p.imagepath5,p.count_comment,p.count_like,p.created as photo_created ,
(select username from users where id = p.user_id) as username ,
(select country from users where id = p.user_id) as country,
(select email from users where id = p.user_id) as email ,
(select image_path from users where id = p.user_id) as image_path ,
(select gender from users where id = p.user_id) as gender,
(select privacy from users where id = p.user_id) as privacy,
(select audio_privacy from users where id = p.user_id) as audio_privacy,
(select video_privacy from users where id = p.user_id) as video_privacy,
(select photo_privacy from users where id = p.user_id) as photo_privacy,
If(pl.user_id && pl.photo_id !='',like_status,0) as islike ,
If(pr.user_id && pr.photo_id !='',1,0) as isreport,
p.user_visibility
from friends as fr
inner join users as u on u.id = (select distinct if (fr.user_id != $user_id,fr.user_id,(fr.to_user_id)) as rd
from friends) && fr.read_status = '1'
inner join photos as p on (p.user_visibility = 'p')
LEFT JOIN photolike as pl ON pl.photo_id = p.photo_id && pl.user_id = $user_id
LEFT JOIN photo_report as pr on pl. photo_id = pr.photo_id && pr.user_id = $user_id
ORDER BY p.photo_id DESC;
答案 0 :(得分:1)
Try using group-by clause instead of distinct.
答案 1 :(得分:1)
使用可缩短时间的mysql indexing