Question

我想以DateTime格式转换字符串

CultureInfo cultureInfoProvider = new CultureInfo("en-US");  
var lastUpdatedDate = updatedVAlue.Max();   //value is 20150219T045452:635599184921416348  
DateTime dt = DateTime.ParseExact(lastUpdatedDate,"yyyyMMddTHHmmss:fff",cultureInfoProvider);

我得到了一个例外字符串未被识别为有效的DateTime。

Answer 1

你可能正在寻找这个......

CultureInfo cultureInfoProvider = new CultureInfo("en-US");

var lastUpdatedDate = updatedVAlue.Max(); //value is 20150219A045452.635-5

DateTime dt = DateTime.ParseExact("20150219A045452.635-5", "yyyyMMddtHHmmss.fffz", cultureInfoProvider);

Answer 2

你在这里。这将修剪你的弦并保持它的3位尾。

  CultureInfo cultureInfoProvider = new CultureInfo("en-US");
  string lastUpdatedDate = updatedVAlue.Max();   //value is 20150219T045452:635599184921416348  
  string[] parse = lastUpdatedDate.Split(':');
  lastUpdatedDate = parse[0] + ":" + parse[1].Substring(0,3);
  DateTime dt = DateTime.ParseExact(lastUpdatedDate,"yyyyMMddTHHmmss:fff",cultureInfoProvider);

在这里测试：https://ideone.com/EIs600

注意：如果可能，请尽量避免在C＃中使用var，在这种情况下，string将完成此任务。

Answer 3

635599184921416348部件有问题。它是太长，只支持最多七个digites。试试这个..

CultureInfo cultureInfoProvider = new CultureInfo("en-US");
var lastUpdatedDate = "20150219T045452:6355991";
DateTime dt = DateTime.ParseExact(lastUpdatedDate, "yyyyMMddTHHmmss:fffffff", cultureInfoProvider);

转换DateTime格式c＃

3 个答案: