Question

有两个View，每个都设置setOnTouchListener()来显示一个popupWindow。当我点击viewA的popupWindowA show.when我点击viewB.I想要popupWindowA dismiss和popupWindowB显示，但是只有popupWindowA dismiss， popupWindowB没有显示。任何人都可以帮助我，非常感谢你！

Answer 1

你是如何处理代码的？以下是一个可行的例子。

    aButton = (Button) findViewById(R.id.button_a);
    bButton = (Button) findViewById(R.id.button_b);

    aButton.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            if (popupWindowB != null && popupWindowB.isShowing()) {
                popupWindowB.dismiss();
            }

            if (popupWindowA == null) {
                popupWindowA = new PopupWindow(v.getContext());
            }
            popupWindowA.setContentView(LayoutInflater.from(v.getContext())
                    .inflate(R.layout.popup_a, null));
            popupWindowA.setHeight(100);
            popupWindowA.setWidth(100);
            popupWindowA.showAtLocation(v, Gravity.CENTER, 0, 0);
        }
    });
    bButton.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            if (popupWindowA != null && popupWindowA.isShowing()) {
                popupWindowA.dismiss();
            }

            if (popupWindowB == null) {
                popupWindowB = new PopupWindow(v.getContext());
            }
            popupWindowB.setContentView(LayoutInflater.from(
                    v.getContext()).inflate(R.layout.popup_b, null));
            popupWindowB.setHeight(150);
            popupWindowB.setWidth(150);
            popupWindowB.showAtLocation(v, Gravity.CENTER, 0, 0);
        }
    });

Answer 2

尝试使用setondismisslistener作为firstpopup并在其中执行所需的操作。

Android popupWindow无法一键显示popupWindowA并关闭popupWindowB

2 个答案: