在Spring RESTful控制器中获取404

时间:2015-03-15 21:17:22

标签: java spring rest spring-mvc

我想在春天的mvc做一个宁静的服务。这是我的控制器代码,

@Controller
@RequestMapping("/manageuser")
public class ManageUserController {

    @RequestMapping(value = "/deleteuser/{user}", method = RequestMethod.GET)
    @ResponseStatus(value = HttpStatus.OK)
    protected void deleteUser(@PathVariable String user, ModelMap model) {
        System.out.println(user);
    }

    @RequestMapping(value = "/adduser/{user}", method = RequestMethod.GET)
    @ResponseStatus(value = HttpStatus.OK)
    protected void addUser(@PathVariable String user, ModelMap model) {
        System.out.println(user);
    }

}

我的manageuser-servelt.xml

<context:component-scan base-package="com.example.web" use-default-filters="false" 
>
<context:include-filter type="annotation" expression="org.springframework.stereotype.Controller"/>
</context:component-scan>


<mvc:annotation-driven />

<bean
    class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="prefix" value="/WEB-INF/" />
    <property name="suffix" value=".jsp" />
</bean>

我的web.xml内容,

    <servlet>
        <servlet-name>manageuser</servlet-name>
        <servlet-class>
           org.springframework.web.servlet.DispatcherServlet
        </servlet-class>
        <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>classpath:manageuser-servlet.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>
 <servlet-mapping>
        <servlet-name>manageuser</servlet-name>
        <url-pattern>/manageuser</url-pattern>
    </servlet-mapping>

如果我导航到localhost / manageuser / adduser / Barney,我将获得404。我在这做错了什么?这是使用spring-mvc的RESTful服务的正确方法吗?

1 个答案:

答案 0 :(得分:0)

&#34; System.out.println(用户)&#34;显示用户?如果没有,那么您的映射会出现问题。

点击此处查看其他博客:http://www.breathejava.com/restful-web-service-tutorial-spring-xml/