Question

我无法让扫描仪等待用户输入。我的问题出在以下几行代码中： System.out.println("Enter the day of the month: "); newOnetime.setDay(scan.nextInt()); scan.nextLine(); System.out.println("Enter the year: "); newOnetime.setYear(scan.nextInt());

我无法让用户输入年份，因为扫描仪只是跳过它。这是我的控制台输出从调试中看起来的样子：

按1进行新的一次约会（假设我按1）

输入约会的说明：牙医访问

输入约会月份： 3

输入当月的日期：

输入年份：

^^就在那里，用户无法放入年份，因为控制台假设该数字适用于日期和年份。

如果这是一个简单的解决方案，我道歉。我不是扫描仪的最大粉丝，通常我会被细微的差别所绊倒。谢谢！

这是我的程序的驱动程序：包预约;

import java.util.Scanner;

import Appointment.Appointment;
import Appointment.Daily;
import Appointment.Monthly;
import Appointment.Onetime;

public class AppointmentBookDriver {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        System.out.println("Press 1 for new one time appointment");
        Onetime.createOneTime(scan);
}

这是一次性课程：包预约;

import java.util.Scanner;


public class Onetime extends Appointment{
    public Onetime(String description, int month, int day, int year) {
         super(description, month, day, year);

    }
/**
 * this method creates a new onetime appt. I realize it is a lengthy
 * method but it is necessary and I couldn't logically break it into
 * smaller methods. 
 * @param scan the scanner that is passed from the driver class
 */
public static void createOneTime(Scanner scan) {
    Onetime newOnetime = new Onetime(null, 0, 0, 0);

    System.out.println("Enter a description of the appointment: ");
    newOnetime.setDescription(scan.nextLine());

    System.out.println("Enter the month of your appointment: ");
    if (scan.hasNextInt()) {
        int month = 0;
        if (month > 0 && month < 13) {
        month = scan.nextInt();
        }
    } else if (scan.hasNextLine()){
        String monthString = scan.next().toLowerCase();
        switch (monthString) {
        case "january": newOnetime.setMonth(1); break;
        case "february": newOnetime.setMonth(2); break;
        case "march": newOnetime.setMonth(3); break;
        case "april": newOnetime.setMonth(4); break;
        case "may": newOnetime.setMonth(5); break;
        case "june": newOnetime.setMonth(6); break;
        case "july": newOnetime.setMonth(7); break;
        case "august": newOnetime.setMonth(8); break;
        case "september": newOnetime.setMonth(9); break;
        case "october": newOnetime.setMonth(10); break;
        case "november": newOnetime.setMonth(11); break;
        case "december": newOnetime.setMonth(12); break;
        default: 
        {System.out.println("Please enter an integer representing a month...");
        newOnetime.setMonth(scan.nextInt());
        }
        }
     }
    System.out.println("Enter the day of the month: ");
    newOnetime.setDay(scan.nextInt());
    scan.nextLine();
    System.out.println("Enter the year: ");
    newOnetime.setYear(scan.nextInt());
    scan.nextLine();
}

}

Answer 1

我只能说这对我来说很好用：

import java.util.Scanner;

class Test {
    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        System.out.println("Enter the day of the month: ");
        System.out.println("You typed: " + scan.nextInt());
        System.out.println("Enter the year: ");
        System.out.println("You typed: " + scan.nextInt());
    }
}

Scanner每次都会阻止，并等待来自System.in的输入。

Answer 2

我决定取消我的switch语句，只强制用户输入为1-12（含）的数字。这样做可以让我保持用户输入的最高点，而且我不必担心凌乱的慢速切换。感谢您的投入，但我决定以不同的方式设计该程序！对不起，如果我浪费了任何人的时间。

扫描仪不会等待用户输入

2 个答案: