错误org.json.JSONException：类型为java.lang.Integer时出错的值1无法转换为布尔值

Question

这是我的剧本：

＆＃13;

＆＃13;

public class LoginActivity extends Activity {
	
	private static final String TAG = MainActivity.class.getSimpleName();
	private Button btnLogin;
	private Button btnLinkToRegister;
	private EditText inputEmail;
	private EditText inputPassword;
	private ProgressDialog pDialog;
	private SessionManager session;

	@Override
	public void onCreate(Bundle savedInstanceState) {
		super.onCreate(savedInstanceState);
		setContentView(R.layout.activity_login);

		inputEmail = (EditText) findViewById(R.id.email);
		inputPassword = (EditText) findViewById(R.id.password);
		btnLogin = (Button) findViewById(R.id.btnLogin);
		btnLinkToRegister = (Button) findViewById(R.id.btnLinkToRegisterScreen);

		
		pDialog = new ProgressDialog(this);
		pDialog.setCancelable(false);

		
		session = new SessionManager(getApplicationContext());

		
		if (session.isLoggedIn()) {
			
			Intent intent = new Intent(LoginActivity.this, MainActivity.class);
			startActivity(intent);
			finish();
		}

		
		btnLogin.setOnClickListener(new View.OnClickListener() {

			public void onClick(View view) {
				String email = inputEmail.getText().toString();
				String password = inputPassword.getText().toString();

				
				if (email.trim().length() > 0 && password.trim().length() > 0) {
					
					checkLogin(email, password);
				} else {
					
					Toast.makeText(getApplicationContext(),
							"Please enter the credentials!", Toast.LENGTH_LONG)
							.show();
				}
			}

		});

		
		btnLinkToRegister.setOnClickListener(new View.OnClickListener() {

			public void onClick(View view) {
				Intent i = new Intent(getApplicationContext(),
						RegisterActivity.class);
				startActivity(i);
				finish();
			}
		});

	}


	private void checkLogin(final String email, final String password) {
		
		String tag_string_req = "req_login";

		pDialog.setMessage("Logging in ...");
		showDialog();

		StringRequest strReq = new StringRequest(Method.POST,
				AppConfig.URL_REGISTER, new Response.Listener<String>() {

					@Override
					public void onResponse(String response) {
						Log.d(TAG, "Login Response: " + response.toString());
						hideDialog();

						try {
							JSONObject jObj = new JSONObject(response);
							boolean error = jObj.getBoolean("error");

							
							if (!error) {
								
								session.setLogin(true);

								
								Intent intent = new Intent(LoginActivity.this,
										MainActivity.class);
								startActivity(intent);
								finish();
							} else {
								
								String errorMsg = jObj.getString("error_msg");
								Toast.makeText(getApplicationContext(),
										errorMsg, Toast.LENGTH_LONG).show();
							}
						} catch (JSONException e) {
							
							e.printStackTrace();
						}

					}
				}, new Response.ErrorListener() {

					@Override
					public void onErrorResponse(VolleyError error) {
						Log.e(TAG, "Login Error: " + error.getMessage());
						Toast.makeText(getApplicationContext(),
								error.getMessage(), Toast.LENGTH_LONG).show();
						hideDialog();
					}
				}) {

			@Override
			protected Map<String, String> getParams() {
				
				Map<String, String> params = new HashMap<String, String>();
				params.put("tag", "login");
				params.put("idm", email);
				params.put("pwd", password);

				return params;
			}

		};

		
		AppController.getInstance().addToRequestQueue(strReq, tag_string_req);
	}

	private void showDialog() {
		if (!pDialog.isShowing())
			pDialog.show();
	}

	private void hideDialog() {
		if (pDialog.isShowing())
			pDialog.dismiss();
	}
}

＆＃13;

＆＃13;

＆＃13;

并且logcat显示：

  

org.json.JSONException：类型为java.lang.Integer时出错的值为1   无法转换为布尔值

我使用此脚本使用我自己的数据库创建登录页面。这个脚本使用电子邮件作为用户名，但在我的数据库中，我使用数字作为用户名。

Answer 1

你的问题在于：

boolean error = jObj.getBoolean("error");

如果你的json对象中的“error”不是“true”或“false”，你将得到异常：

  

java.lang.Integer类型的错误值1无法转换为   布尔值。

而是使用

int intError = jObj.getInt("error");
boolean error = (intError > 0) ? true : false;

Answer 2

JSONObject jObj = new JSONObject(response);
boolean error = jObj.getBoolean("error");

您的回复＆＃34;错误＆＃34; object不是布尔值，因此您可以根据exception消息将其转换为String或Integer。如下所示

JSONObject jObj = new JSONObject(response);
boolean error = jObj.getString("error");
// or
JSONObject jObj = new JSONObject(response);
boolean error = jObj.getInteger("error");