根据KeyboardView.OnKeyboardActionListener.onRelease()
SDK文档,“对于重复的密钥,只调用一次”。但是,如果我使用Android软键板示例将'a'键的isRepeatable设置为true,并记录onPress()
,onKey()
和onRelease()
方法调用,我会按预期重复,但我观察单个按下/重复/释放序列的以下日志:
I/SoftKeyboard(31467): onPress: 97
I/SoftKeyboard(31467): onKey: 97
I/SoftKeyboard(31467): onRelease: 97
I/SoftKeyboard(31467): onKey: 97
I/SoftKeyboard(31467): onRelease: 97
I/SoftKeyboard(31467): onKey: 97
I/SoftKeyboard(31467): onRelease: 97
I/SoftKeyboard(31467): onKey: 97
I/SoftKeyboard(31467): onRelease: 97
I/SoftKeyboard(31467): onKey: 97
I/SoftKeyboard(31467): onRelease: 97
如何确定触控设备的确切释放时间?谢谢,D。
编辑(由Paul Boddington编辑2015年7月30日)
虽然我不是OP,但我想提供一个显示问题的完整示例。
MyActivity
:
public class MyActivity extends Activity {
private static final String TAG = "MyActivity";
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_my);
KeyboardView keyboardView = (KeyboardView) findViewById(R.id.keyboard_view);
keyboardView.setKeyboard(new Keyboard(this, R.xml.keyboard));
keyboardView.setOnKeyboardActionListener(new KeyboardView.OnKeyboardActionListener() {
@Override
public void onPress(int i) {
Log.i(TAG, "onPress: " + i);
}
@Override
public void onKey(int i, int[] ints) {
Log.i(TAG, "onKey: " + i);
}
@Override
public void onRelease(int i) {
Log.i(TAG, "onRelease: " + i);
}
@Override public void onText(CharSequence charSequence) {}
@Override public void swipeLeft() {}
@Override public void swipeRight() {}
@Override public void swipeDown() {}
@Override public void swipeUp() {}
});
}
}
keyboard.xml
:
<?xml version="1.0" encoding="utf-8"?>
<Keyboard xmlns:android="http://schemas.android.com/apk/res/android">
android:layout_height="wrap_content"
android:layout_width="match_parent"
>
<Row
android:keyWidth="25%p"
android:keyHeight="60dp">
<Key android:codes="0" android:keyLabel="0" android:isRepeatable="true"/>
<Key android:codes="1" android:keyLabel="1" />
<Key android:codes="2" android:keyLabel="2" />
<Key android:codes="3" android:keyLabel="3" />
</Row>
</Keyboard>
activity_my.xml
:
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent">
<android.inputmethodservice.KeyboardView
android:id="@+id/keyboard_view"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:focusable="true"
android:focusableInTouchMode="true"
/>
</LinearLayout>
答案 0 :(得分:2)
我无法弄清楚如何修复KeyboardView
以正确发出可重复键的onRelease()
。因此,我提出了一种解决方法,通过查看MotionEvent.ACTION_UP
来识别发布。您只对可重复键执行此操作,并忽略这些键的onRelease()
事件。
private List<Integer> mRepeatableKeys = new ArrayList<Integer>();
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
final KeyboardView keyboardView = (KeyboardView) findViewById(R.id.keyboard_view);
keyboardView.post(new Runnable() {
@Override
public void run() {
for( Keyboard.Key key : keyboardView.getKeyboard().getKeys() )
{
if(key.repeatable) mRepeatableKeys.add(key.codes[0]);
}
}
});
keyboardView.setOnTouchListener(new View.OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
if (event.getAction() == MotionEvent.ACTION_UP) {
if(mTrackingRepeatableKey != -1)
{
Log.i(TAG, "Repeatable key released: " + mTrackingRepeatableKey);
mTrackingRepeatableKey = -1;
}
}
return false;
}
});
keyboardView.setKeyboard(new Keyboard(this, R.xml.keyboard));
keyboardView.setOnKeyboardActionListener(mKeyboardActionListener);
}
private int mTrackingRepeatableKey = -1;
KeyboardView.OnKeyboardActionListener mKeyboardActionListener = new KeyboardView.OnKeyboardActionListener() {
@Override
public void onPress(int i) {
Log.i(TAG, "onPress: " + i);
if( mRepeatableKeys.contains(i))
{
mTrackingRepeatableKey = i;
}
}
@Override
public void onKey(int i, int[] ints) {
if( mRepeatableKeys.contains(i))
{
Log.i(TAG, "onKey Repeat: " + i);
return;
}
Log.i(TAG, "onKey: " + i);
}
@Override
public void onRelease(int i) {
// Ignore release for repeatable keys
if( mRepeatableKeys.contains(i)) return;
Log.i(TAG, "onRelease: " + i);
}
@Override
public void onText(CharSequence text) {
}
@Override
public void swipeLeft() {
}
@Override
public void swipeRight() {
}
@Override
public void swipeDown() {
}
@Override
public void swipeUp() {
}
};
在Android 5.1上测试过。现在的日志是:
I/MainActivity﹕ onPress: 1
I/MainActivity﹕ onKey Repeat: 1
I/MainActivity﹕ onKey Repeat: 1
I/MainActivity﹕ onKey Repeat: 1
I/MainActivity﹕ onKey Repeat: 1
I/MainActivity﹕ onKey Repeat: 1
I/MainActivity﹕ onKey Repeat: 1
I/MainActivity﹕ onKey Repeat: 1
I/MainActivity﹕ onKey Repeat: 1
I/MainActivity﹕ Repeatable key released: 1
如果你想要,你可以扩展KeyboardView,并在其中包含所有这些丑陋的逻辑。
答案 1 :(得分:0)
我没有做很多Android编程,但是使用onLongPress方法检查是否仍然在onRelease方法中按下了键是不是很简单?
@Override
public void onRelease(int i) {
if(keyboardView.onLongPress(i){
//do nothing
}
else{
Log.i(TAG, "onRelease: " + i);
}
}
除非我弄错了,如果你的手指仍然在钥匙上,那么该方法应该返回true,当你停止时,该方法应该返回false。