Question

Hangman游戏

当满足参数时，它不会停止循环有没有不同的方法来做到这一点或者我编码错了抱歉，我是一周前开始编码的菜鸟提前谢谢

这是我的代码：

#include <iostream>
#include <string>


using namespace std;

int main()
{

string sword = "---";
string swordans = "nhs";
char guess;
int guessnum;
guessnum = 0;
int incguessnum;
incguessnum = 0;


while ((((guessnum < 7) && (incguessnum < 6)) || **(sword == swordans)**))
{
    cout<<"Please guess a letter"<<endl;           (   /\  )
    cin>>guess;                                    (   ||  ) 
                                                   (   ||  ) 
    if (guess == 'n')                          (pver here it is not stopping
    {                                           the loop when the replaced
        guessnum ++;                            sword = swordans string)

        cout<<"You have guessed "<< guessnum <<" time(s)"<< endl;
        cout<<"Correct"<<endl;
        sword.replace(0,1,"n");
        cout<<sword<<endl;
    }

    else if (guess == 'h')
    {
        guessnum ++;
        cout<<"You have guessed "<< guessnum <<" time(s)"<< endl;
        cout<<"Correct"<<endl;
        sword.replace(1,1,"h");
        cout<<sword<<endl;
    }
    else if (guess == 's')
    {
        guessnum ++;
        cout<<"You have guessed "<< guessnum <<" time(s)"<< endl;
        cout<<"Correct"<<endl;
        sword.replace(2,1,"s");
        cout<<sword<<endl;
    }
    else 
    {
        guessnum ++;
        cout<<"You have guessed "<< guessnum <<" time(s)"<< endl;
        incguessnum++;
        cout<<"Incorrect"<<endl;
        if (incguessnum == 1)
        {
            cout<<" o"<<endl;
        }
        else if (incguessnum == 2)
        {
            cout<<" o"<<endl;
            cout<<" |"<<endl;
        }
        else if (incguessnum == 3)
        {
            cout<<" o"<<endl;
            cout<<" |"<<endl;
            cout<<" |"<<endl;
        }else if (incguessnum == 4)
        {
            cout<<" o"<<endl;
            cout<<" |"<<endl;
            cout<<" |"<<endl;
            cout<<"/"<<endl;
        }else if (incguessnum == 5)
        {
            cout<<" o"<<endl;
            cout<<" |"<<endl;
            cout<<" |"<<endl;
            cout<<"/ \\"<<endl;
        }else if (incguessnum == 6)
        {
            cout<<"  o"<<endl;
            cout<<"  |"<<endl;
            cout<<"--|"<<endl;
            cout<<" / \\"<<endl;

        }
        else 
        {
            cout<<"  o"<<endl;
            cout<<"  |"<<endl;
            cout<<"--|--"<<endl;
            cout<<" / \\"<<endl;
        }

    }
}


system ("pause");
return(0);
}

Answer 1

while ((((guessnum < 7) && (incguessnum < 6)) || (sword == swordans)))

此循环将继续，同时猜测次数小于7且错误猜测小于6.当剑等于剑侠时，它将继续。

您可以将其替换为所需效果：

while(guessnum < 7 && incguessnum < 6 && sword != swordans)

它也读得更整齐;）

Answer 2

如果目标是在sword == swordans时终止循环，则需要将条件调整为&& (sword != swordans)。你只想继续循环，如果玩家没有用完他们所有的猜测并且他们还没有解决这个难题。

就目前而言，一旦字符串相等，你的循环将无限延续 - 肯定不是你想要的。

您的情况正在被承认＆＃34;准确，但由于条件错误，你不会看到所期望的行为。

为什么我的while参数没有得到确认

2 个答案: