Question

我正在编写这个猜谜游戏，它允许用户输入一个数字作为最大数字。

然后，随机生成器将选择1和用户输入的最大数字之间的数字。

它将保存并显示高猜测次数和低猜测次数。

我遇到的问题是循环程序并验证。

在用户输入错误的输入后，我无法让程序循环回来，即不是整数。

我希望它在显示错误消息后循环返回另一个猜测。

我正在使用try / catch但是在错误消息之后程序不允许用户输入另一个号码来继续游戏。

import java.util.ArrayList;
import java.util.Random;
import javax.swing.JOptionPane;

public class guessinggame { // class name

    public static void main(String[] args) { // main method

        String smax = JOptionPane.showInputDialog("Enter your maximum number for the Guessing Game:");
        int max = Integer.parseInt(smax);

        do {
            if (max > 10000) {
                JOptionPane.showMessageDialog(null, "Oh no! Please keep your number less than 10,000.");
                smax = JOptionPane.showInputDialog("Enter your maximum number for the Guessing Game:");
                max = Integer.parseInt(smax);
            }
        } while (max > 10000);

        int answer, guess = 0, lowcount = 0, highcount = 0, game;
        String sguess;
        Random generator = new Random();
        answer = generator.nextInt(max) + 1;

        ArrayList<String> buttonChoices = new ArrayList<>(); // list of string arrays called buttonChoices 
        buttonChoices.add("1-" + max + " Guessing Game");

        Object[] buttons = buttonChoices.toArray(); // turning the string arrays into objects called buttons

        game = JOptionPane.showOptionDialog(null, "Play or Quit?", "Guessing Game",
                JOptionPane.PLAIN_MESSAGE, JOptionPane.QUESTION_MESSAGE,
                null, buttons, buttonChoices.get(0));

        do {
            sguess = JOptionPane.showInputDialog("I am thinking of a number between 1 and " + max + ". Have a guess:");
            try {
                guess = Integer.parseInt(sguess);
            } catch (Exception nfe) {
                JOptionPane.showMessageDialog(null, "That was not a number! ");
            }

            if (guess < answer) {
                JOptionPane.showMessageDialog(null, "That is too LOW!");
                lowcount++;

            } else if (guess > answer) {
                JOptionPane.showMessageDialog(null, "That is too HIGH!");
                highcount++;
            }

        } while (guess != answer);
        JOptionPane.showMessageDialog(null, "Well Done!" + "\n---------------" + "\nThe answer was " + answer + "\nLow Guesses: " + lowcount
                + "\nHigh Guesses: " + highcount + "\n\nOverall you guessed: " + (lowcount + highcount) + " Times");

        System.exit(0);
    }
}

Answer 1

把它放在我的机器上，然后循环好了。它虽然破碎了;默认情况下，guess为0，并在异常后继续执行代码。如果发生随机数为0，程序将退出，因为它是正确的猜测。假设你的机器上发生了类似的事情？

您还没有将保护逻辑放在最初的“最大数量”位置。

Answer 2

在try catch中使用continue;。

代码就像

        try {
                guess = Integer.parseInt(sguess);
            } catch (Exception nfe) {
                JOptionPane.showMessageDialog(null, "That was not a number! ");
                continue;
            }

Answer 3

虽然我无法看到您所描述的问题，但我建议您将比较代码放在try块中，这样您就可以确保在进行任何比较之前正确设置guess变量：< / p>

        try {
            guess = Integer.parseInt(sguess);
            if (guess < answer) {
                JOptionPane.showMessageDialog(null, "That is too LOW!");
                lowcount++;

            } else if (guess > answer) {
                JOptionPane.showMessageDialog(null, "That is too HIGH!");
                highcount++;
            }
        } catch (Exception nfe) {
            JOptionPane.showMessageDialog(null, "That was not a number! ");
        }

如何修复这个基本程序？ Java do-while循环

3 个答案: