Question

抱歉格式化问题！我不知道它在这个网站上有效:(

我试图在1月份的销售表中仅返回最高的总计，但它会返回该月的每笔销售而不仅仅是最高的。

select
  EMP.FirstName,
  EMP.LastName,
  EMP.Email,
  SAL.SaleNumber,
  SAL.SaleDate,
  max(SAL.Total) Total
from 
  Employee EMP
  INNER JOIN Sale SAL
    ON EMP.EmployeeNumber = SAL.EmployeeNumber

--Assuming the month is January of 2015, because there were no sales for this month (March).
where
  SAL.SaleDate between '20150101 00:00:00.000' and '20150131 23:59:59.997'

group by
  EMP.FirstName,
  EMP.LastName,
  EMP.Email,
  SAL.SaleNumber,
  SAL.SaleDate,
  SAL.Total

Answer 1

我认为您希望在给定的时间范围内获得每位员工的最高销售额？如果是这样，一种选择是使用排名函数，例如row_number：

with cte as (
select
  EMP.FirstName,
  EMP.LastName,
  EMP.Email,
  SAL.SaleNumber,
  SAL.SaleDate,
  SAL.Total,
  row_number() over (partition by EMP.EmployeeNumber 
                     order by SAL.Total DESC) rn
from 
  Employee EMP
  INNER JOIN Sale SAL
    ON EMP.EmployeeNumber = SAL.EmployeeNumber
where
  SAL.SaleDate >= '20150101 00:00:00.000' and 
  SAL.SaleDate < '20150201 00:00:00.000'
)
select *
from cte
where rn = 1

另请注意，我建议您使用>=和<进行此类日期过滤。

Answer 2

我假设正在寻找最畅销的产品。您的查询获得每个销售数量的最高销售额，最终成为每次销售。

select top 1
  EMP.FirstName,
  EMP.LastName,
  EMP.Email,
  SAL.SaleNumber,
  SAL.SaleDate,
  SAL.Total
from 
  Employee EMP
  INNER JOIN Sale SAL
    ON EMP.EmployeeNumber = SAL.EmployeeNumber

Order by sal.total desc

我的选择中的SQL 2012我的MAX没有显示最大值

2 个答案: