正则表达式：排除捕获可能存在或不存在的模式

Question

我有类似字符串的一些变体：

#This is a string
#This is another string (with some info in parentheses)

我希望通过正则表达式运行它们并在第一个捕获组中捕获"#This"，在第二个捕获组中捕获"a string"或"another string"。

注意在第二个字符串中我不想要括号＆＃39;或其内容。

我尝试了一堆或正则表达式提供以下输出

/#(.*) is (.*)/：最简单的正则表达式，但不排除括号及其内容

String1 Match1:     This
String1 Match2:     a string
String2 Match1:     This
String2 Match2:     another string (with some info in parentheses)

/#(.*) is (.*)\(/添加左括号仅适用于实际拥有它的字符串

String1 Match1:     null
String1 Match2:     null
String2 Match1:     This
String2 Match2:     another string

/#(.*) is (.*)\(*/使其*可选（我猜错了）

String1 Match1:     This
String1 Match2:     a string
String2 Match1:     This
String2 Match2:     another string (with some info in parentheses)

/#(.*) is (.*)\(?/使?（相同结果）

可选

String1 Match1:     This
String1 Match2:     a string
String2 Match1:     This
String2 Match2:     another string (with some info in parentheses)

/#(.*) is (.*?)\(*/让它变得非贪婪

String1 Match1:     This
String1 Match2:     null
String2 Match1:     This
String2 Match2:     null

＆＃13;

＆＃13;

var string1 = "#This is a string";
var string2 = "#This is another string (with some info in parentheses)";

// var regex = /#(.*) is (.*)/;
// var regex = /#(.*) is (.*)\(/;
// var regex = /#(.*) is (.*)\(*/;
   var regex = /#(.*) is (.*)\(?/;
// var regex = /#(.*) is (.*?)\(*/;

var match1 = string1.match(regex);
var match2 = string2.match(regex);

alert('String1 Match1: \t' + ((match1&&match1[1])?match1[1]:'null') + '\nString1 Match2: \t' + ((match1&&match1[2])?match1[2]:'null') +
    '\nString2 Match1: \t' + ((match2&&match2[1])?match2[1]:'null') + '\nString2 Match2: \t' + ((match2&&match2[2])?match2[2]:'null') );

＆＃13;

＆＃13;

＆＃13;