Question

我必须从两个sql语句的结果中选择常见的颜色c1，c2，c3。

1）

select c1, c2, c3,count(c3)  from (select * from form_name
where data_created >'1273446000' and data_creazione<'1274569200')
group by c1,c2, c3 having count(c3)>1

2）

select c1, c2, c3,count(c3)  from (select * from form_name 
where data_created>'1272236400' and data_creazione<'1274569200')
group by c1,c2, c3 having count(c3)>2

我需要选择c1，c2，c3在查询结果中同样和常见。

怎么可能这样做......有人可以帮忙吗？

Answer 1

从选择列表中删除count(c3)，它可以不同（HAVING子句保证这一点），OP只想比较c1，c2和c3。如果COUNT(c3)列不同，哪些行可以共同使用？没有或一些，它会有所不同。同时删除派生表，它们不是必需的。所以试试：

select 
    c1, c2, c3  
    from form_name
    where data_created >'1273446000' and data_creazione<'1274569200'
    group by c1,c2, c3 
    having count(c3)>1
INTERSECT
select 
    c1, c2, c3
    from form_name 
    where data_created>'1272236400' and data_creazione<'1274569200'
    group by c1,c2, c3 
    having count(c3)>2

Answer 2

您是否尝试使用'UNION'加入2个查询？

例如

select c1, c2, c3,count(c3)  from (select * from form_name
where data_created >'1273446000' and data_creazione<'1274569200')
group by c1,c2, c3 having count(c3)>1    
union    
select c1, c2, c3,count(c3)  from (select * from form_name 
where data_created>'1272236400' and data_creazione<'1274569200')
group by c1,c2, c3 having count(c3)>2

Answer 3

我认为INTERSECT会解决您的问题。更多信息here。

select c1, c2, c3,count(c3)  from (select * from form_name
where data_created >'1273446000' and data_creazione<'1274569200')
group by c1,c2, c3 having count(c3)>1    
INTERSECT
select c1, c2, c3,count(c3)  from (select * from form_name 
where data_created>'1272236400' and data_creazione<'1274569200')
group by c1,c2, c3 having count(c3)>2

Answer 4

您可以使用派生表，然后将它们连接在一起以获得所需的结果。

select a.c1, a.c2, a.c3, a.acount, b.bcount
From 
(select c1, c2, c3, count(*) as acount  from (select * from form_name 
where data_created >'1273446000' and data_creazione<'1274569200') 
group by c1,c2, c3 having count(c3)>1) a
join 
(select c1, c2, c3, count(*) as bcount from (select * from form_name  
where data_created>'1272236400' and data_creazione<'1274569200') 
group by c1,c2, c3 having count(c3)>2)b 
    on a.c1 = b.c1 and a.c2 = b.c2 and a.c3 = b.c3

需要结合两个select语句的常见结果

4 个答案: