Question

请帮助格式化我的输出。

我被要求“编写一个程序，显示所有闰年，每行十个，在二十一世纪（从2001年到2100年），只有一个空格分开”。

虽然我得到了正确的结果，但它不符合要求的格式。

提前致谢

    public class Leapyear {
    public static void main(String[] args) {
        //declare variabls;
     int year;
     int count=1;
     int yearsperline = 10;
     //loop
     for(year=2001;2001<=2100;year++){
         if((year%4==0 && year%100!=0) || (year%400==0))
             System.out.print(year+",");
           if ( year ==2100)
               break;
        while (count%10==0)
        System.out.println();
     }
     }    

   }

Answer 1

你可以这样写：

//declare variables;
final int YEARS_PER_LINE = 10;
final int START_YEAR = 2001;
//loop
for(int year = START_YEAR; year <= 2100; year++){
    System.out.print(year);

    if((year - START_YEAR) % YEARS_PER_LINE == (YEARS_PER_LINE - 1)) {
        System.out.println();
    } else {
        System.out.print(",");
    }
}

Answer 2

试试这个：

public class LeapYear
{
    public static void main(String[] args)
    {
        // declare variables
        final int startYear = 2001;
        final int endYear = 2100;
        final int yearsPerLine = 10;

        // loop
        for (int year = startYear, count = 0; year <= endYear; year++)
        {
            if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
            {
                if (count % yearsPerLine != 0)
                    System.out.print(" ");
                else if (count > 0 && count % yearsPerLine == 0)
                    System.out.println();

                System.out.print(year);
                ++count;
            }
        }
    }
}

Answer 3

    int startFromYear = 2001;
    int stopAtYear = 2100;
    int count = 0;

    for(int i = startFromYear; i <= stopAtYear; i++){
        if((i % 4 == 0 && i % 100 != 0)||(i % 400 == 0)){
            System.out.print(i + " ");
            count++;
            if(count % 10 ==0)
                System.out.println();
       }    

  }

Answer 4

100％正确！而且容易理解。

public class LeapYears
{
    public static void main(String[] args)
    {
        int count = 0;
        for(int i = 2001; i <= 2100; i++)
        {
            if ((i % 4 == 0 && i % 100 != 0)||(i % 400 == 0))
            {   
                count++;
                //if count is 10 then start a new line. 
                if(count % 10 == 0)
                {
                    System.out.println(i);
                }   
                //if count is smaller 10 then in the same line 
                else
                {
                    System.out.print(i + " ");
                }
            }
        }
    }
}

如何获得每线10个 - 年

4 个答案: