通过char的第一个位置的char将char *拆分为两个char *

Question

我有一个char *：

char* version = "10.5.108";

我希望通过char分隔符获得两个新的char *。

char delimiter = '.';

执行以下代码后的代码：

printf("|%s|%s|", first, second);

应该导致：

|10|5.108|

Answer 1

抓住：！）

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stddef.h>


int main(void) 
{
    char *version = "10.5.108";
    char *first, *second;

    if ( ( second = strchr( version, '.' ) ) == NULL )
    {
        first = malloc( strlen( version ) + 1 );
        strcpy( first, version );
        second = malloc( sizeof( char ) );
        *second = '\0';
    }
    else
    {
        ptrdiff_t n = second - version;
        first = malloc( ( n + 1 ) * sizeof( char ) );
        second = malloc ( ( strlen( version ) - n ) * sizeof( char ) );

        strncpy( first, version, n );
        first[n] = '\0';
        strcpy( second, version + n + 1 );
    }

    printf( "|%s|%s|", first, second );

    free( first );
    free( second );

    return 0;
}

输出

|10|5.108|