Question

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <string.h>
#include <iostream>
#include <cstdlib>
using namespace std; 
#include "bcio2.h"

int error, x;
char totalimpulse[80], averageimpulse[80], ejection[50], emptymass[50], enginemass[50], fuelmass[50];
char launch[50];
void validate_number();

int main(void)
{
    clrscr();
    do{
        printf("\nTotal Impulse delivered: ");
        gets(totalimpulse);
        validate_number();
    } while (error != 0);

    do{
        printf("\nAverage Impulse delivered: ");
        gets(averageimpulse);
        validate_number();
    } while (error != 0);

    do{
        printf("\nTime that ejection charge fires: ");
        gets(ejection);
        validate_number();
    } while (error != 0);

    do{
        printf("\nThe mass of the empty vehicle: ");
        gets(emptymass);
        validate_number();
    } while (error != 0);

    do{
        printf("\nThe mass of the engine: ");
        gets(enginemass);
        validate_number();
    } while (error != 0);

    do{
        printf("\nThe mass of fuel: ");
        gets(fuelmass);
        validate_number();
    } while (error != 0);

printf("\nRocket parameters entered: \n");
   printf("\nTotal Impulse delivered: %s\n", totalimpulse);
   printf("Average Impulse delivered: %s\n", averageimpulse);
   printf("Time that ejection charge fires: %s\n", ejection);
   printf("The mass of the empty vehicle: %sg\n", emptymass);
   printf("The mass of the engine: %sg\n", enginemass);
   printf("The mass of fuel: %sg\n", fuelmass);

char ans;
do
{
       cout<< "\nLaunch simulation? (Y/N) : \n";
       cout<< "You must type a 'Y' or an 'N'.\n";
       cin >> ans;
}
while((ans !='Y')&&(ans !='N')&&(ans !='y')&&(ans !='n'));

if (ans == 'N')
    {
        getchar();
        return 0;
    }
    else if (ans == 'Y')
    {
        // do something, calculations display page
        return 0;
    }
}

   /************ Test all input in range 0 to 9 ****************/
   void validate_number()
   {
       int errange = 0, numonly = 0, errlength = 0;
       /********* validate numbers ********/
       error = 0;

       for (x = 0; x<strlen(totalimpulse); x++){

           if (totalimpulse[x] >= '0' && totalimpulse[x] <= '9');    else{
               numonly++;
               error++;
           }

       for (x = 0; x<strlen(averageimpulse); x++){

           if (averageimpulse[x] >= '0' && averageimpulse[x] <= '9');    else{
               numonly++;
               error++;
           }

       for (x = 0; x<strlen(ejection); x++){

           if (ejection[x] >= '0' && ejection[x] <= '9');    else{
               numonly++;
               error++;
           }

       for (x = 0; x<strlen(emptymass); x++){

           if (emptymass[x] >= '0' && emptymass[x] <= '9');    else{
               numonly++;
               error++;
           }

       for (x = 0; x<strlen(enginemass); x++){

           if (enginemass[x] >= '0' && enginemass[x] <= '9');    else{
               numonly++;
               error++;
           }

       for (x = 0; x<strlen(fuelmass); x++){

           if (fuelmass[x] >= '0' && fuelmass[x] <= '9');    else{
               numonly++;
               error++;
           }
       }
       /********* validate range ********/
       if (strlen(totalimpulse) <= 3){
           x = atoi(totalimpulse);

           if (x >= 0 && x <= 256)
               ;
           else{
               errange++;
               error++;
           }
       }
       else{
           errlength++;
           error++;
       }


       /**************** Report errors ******************/
       if (error != 0){
           if (numonly>0)
               printf("\nOnly values in the range 0 to 9 are valid ");
           if (errange>0)
               printf("\nValue must be in the range 0 to 255");
           if (errlength>0)
               printf("\nMore than three values were entered");
       }

我已经计算了21个开口矫正器和21个闭合矫正器，它们似乎都正确定位但我仍然得到错误，任何一双新眼睛可以帮助我吗？我已经多次计算括号，因为我疯了。

这是基本问题的基本错误，但我对于要更改或添加的内容一无所知。

Answer 1

代码中有27个开括号。

[11:05am][wlynch@watermelon ~] fgrep -o '{' /tmp/asd.cc | wc -l
      27
[11:05am][wlynch@watermelon ~] fgrep -o '}' /tmp/asd.cc | wc -l
      21

值得注意的是，这段代码中有两个开括号，但只有一个右括号：

   for (x = 0; x<strlen(totalimpulse); x++){

       if (totalimpulse[x] >= '0' && totalimpulse[x] <= '9');    else{
           numonly++;
           error++;
       }

此外，这不是无效的，但写得非常好：

if (averageimpulse[x] >= '0' && averageimpulse[x] <= '9');    else{

请将其写为：

if (not (averageimpulse[x] >= '0' && averageimpulse[x] <= '9')) {

或：

if (averageimpulse[x] < '0' || averageimpulse[x] > '9')) {

C1075：在左括号'{'匹配之前找到的文件结尾 - 无法解决此问题。

1 个答案: