Question

我必须下载此.txt文件：Link

然后我必须将其解析为.csv并删除所有标题。

我尝试这样做，但它对我不起作用，这是我的代码：

import urllib
import csv

outfilename = "temp.txt"
csvfile = "data.csv" #open('data.csv', 'wb')
url_of_file = "http://www.ceps.cz/_layouts/15/Ceps/_Pages/GraphData.aspx?mode=txt&from=1/1/2011%2012:00:00%20AM&to=1/2/2011%2011:59:59%20PM&hasinterval=True&sol=1&lang=ENG&agr=MI&fnc=AVG&ver=RT&"
urllib.request.urlretrieve(url_of_file, outfilename) 


with open(outfilename, "rb") as infile, open(csvfile, 'wb') as outfile:
    in_txt = csv.reader(infile, delimiter = ';')
    out_csv = csv.writer(outfile)
    out_csv.writerows(in_txt)

在这段代码中，我没有对标题做任何事情，因为即使转换还没有工作。

Answer 1

request中没有urllib名称空间。

替换此行

urllib.request.urlretrieve(url_of_file, outfilename)

有了这个

urllib.urlretrieve(url_of_file, outfilename)

<强>已更新：

您需要导入urllib.request，而不仅仅是urllib。

此外，您需要以文本模式打开文件，而不是二进制模式（即'rb'或'wb'）。

import urllib.request
import csv

outfilename = "temp.txt"
csvfile = "data.csv" #open('data.csv', 'wb')
url_of_file = "http://www.ceps.cz/_layouts/15/Ceps/_Pages/GraphData.aspx?mode=txt&from=1/1/2011%2012:00:00%20AM&to=1/2/2011%2011:59:59%20PM&hasinterval=True&sol=1&lang=ENG&agr=MI&fnc=AVG&ver=RT&"
urllib.request.urlretrieve(url_of_file, outfilename)


with open(outfilename, "r") as infile, open(csvfile, 'w') as outfile:
    in_txt = csv.reader(infile, delimiter = ';')
    out_csv = csv.writer(outfile)
    out_csv.writerows(in_txt)

Answer 2

您可以将此代码用于Python 2：

    import urllib
    import csv
    import urllib2

    outfilename = "temp.txt"
    csvfile = "data.csv" #open('data.csv', 'wb')
    url_of_file = "http://www.ceps.cz/_layouts/15/Ceps/_Pages/GraphData.aspx?mode=txt&from=1/1/2011%2012:00:00%20AM&to=1/2/2011%2011:59:59%20PM&hasinterval=True&sol=1&lang=ENG&agr=MI&fnc=AVG&ver=RT&"
    #urllib.request.urlretrieve(url_of_file, outfilename) 

    response = urllib2.urlopen(url_of_file)
    output = open(outfilename,'wb')
    output.write(response.read())
    output.close()

    with open(outfilename, "rb") as infile, open(csvfile, 'wb') as outfile:
        in_txt = csv.reader(infile, delimiter = ';')
        out_csv = csv.writer(outfile)
        i = 0
        for row in in_txt:
            i +=1
            if i>3:
                out_csv.writerow(row)

Python 3：

    import urllib.request
    import csv

    outfilename = "temp.txt"
    csvfile = "data.csv"
    url_of_file = "http://www.ceps.cz/_layouts/15/Ceps/_Pages/GraphData.aspx?mode=txt&from=1/1/2011%2012:00:00%20AM&to=1/2/2011%2011:59:59%20PM&hasinterval=True&sol=1&lang=ENG&agr=MI&fnc=AVG&ver=RT&"
    urllib.request.urlretrieve(url_of_file, outfilename) 

    with open(outfilename, encoding='utf-8') as infile, open(csvfile, 'w', newline='') as outfile:
            in_txt = csv.reader(infile, delimiter = ';')
            out_csv = csv.writer(outfile)
            i = 0
            for row in in_txt:
                i +=1
                if i>3:
                    out_csv.writerow(row)

用';'下载txt分隔符并使用python转换为.CSV

2 个答案: