如何组合StudentProfileID和DateToday的自定义RegNo?
StudentProfileID-是Create Method上自动生成的主键
日期今天 - 格式:031415
创建方法的示例代码
public ActionResult Create([Bind(Include="StudentProfileID,RegNo,EnrollmentDate,LastName,FirstName,MiddleName,Address,ContactNo,MaritalStatus,Birthdate,Birthplace,Age,PositionRank,Years,PRC,SBOOK,MMAP,PPORT,SRC,TraineeType,EndorsedBy,EmergencyPerson,EmergencyAddress,EmergencyContactNo,EmergencyRelationship")] StudentProfile studentprofile)
{
if (ModelState.IsValid)
{
db.StudentProfile.Add(studentprofile);
db.SaveChanges();
return RedirectToAction("Index");
}
return View(studentprofile);
}
我在创建学生档案时遵循了这篇文章 http://www.codeproject.com/Tips/869986/CRUD-operation-with-Entity-Framework-Code-First
我很感激你的帮助。谢谢。
答案 0 :(得分:0)
db.savechanges()之后;我们将获得sudentProfileId如下
if (ModelState.IsValid)
{
db.StudentProfile.Add(studentprofile);
db.SaveChanges();
int studentId = studentprofile.StudentId;
string custRegNo = studetId.toString()+ DateTime.Now;
return RedirectToAction("Index");
}