Question

我有这个装饰器来检查用户是否已登录并且帐户已激活。

def activation_required(func):
    """
    checks if user is registered logged in and activated
    """
    def decorator(request, *args, **kwargs):
        if request.user and request.user.is_authenticated():
            try:
                user = request.user
                if user.active:
                    return func(request, *args, **kwargs)
                else:
                    messages.add_message(request, messages.ERROR, "not activated!")
                    return HttpResponseRedirect(reverse('home'))
            except Exception as e:
                return HttpResponseServerError(repr(e))
        else:
            return HttpResponseRedirect(reverse('home'))
    return decorator

而不是HttpResponseRedirect我想用消息返回ajax错误。这可能吗？怎么样？

function postData(url){
    var ajax_data = {
        message: "",
        return_val: ""
    };
    $.ajax({
        url: url,
        type: "POST",
        dataType: "json",
        data: ajax_data,
        success:function(data){
            alert('ok');
        }, // success
        error: function(data){
            alert(data.message); // <- this should run if user is not activated
        } // error
    }); // ajax
}

Answer 1

添加此导入：

from django.http import HttpResponse

然后，而不是HttpResponseRedirect，返回：

return HttpResponse('Your message here', status=401)

我对所有javascript框架或浏览器都不太了解，但您可能需要添加内容长度，而不是上面的内容，您可以这样做：

response = HttpResponse('Your message here', status=401)
response['Content-Length'] = len(response.content)
return response

Django，如何强制返回ajax错误？

1 个答案: