Question

我想将用户的图像保存到数据库中。

p9_member（member_no，member_name，....，member_photo）

现在，我使用BLOB保存“member_photo”列的图像我现在想做的是：
1.我有一个应用程序需要连接数据库并从数据库中获取图像我也有一个网站做同样的事情我现在正在实施该应用程序。因为我需要发送图像，其中包含名称或ID等成员的一些信息。所以我创建了一个保存所有东西的对象。这是我的PHP代码：

<?PHP
   Class Friends{
var $no;
var $name;
var $photo;
var $status;
var $admin;
public function __construct($no,$name,$photo,$admin,$status){
    $this->name = $name;
    $this->photo = $photo;
    $this->no = $no;
    $this->status=$status;
    $this->admin=$admin;
}
};
include ("../../server_config.php");
$friends = array();
$SQL = "SELECT p9_member.member_no,p9_member.photo AS     PHOTO,p9_member.name,p9_member.photo FROM p9_member, p9_friends WHERE p9_member.member_no = p9_friends.member_no2 AND p9_friends.member_no1 =".$_POST['memberno'];
$result = mysqli_query($con,$SQL);
if (mysqli_num_rows($result)>0) {
        while($row = mysqli_fetch_array($result)){
            $friends[] = new Friends($row['member_no'],$row['name'],$row['photo'],null,null);
        }
    }else
        $friends[] = 0;
    echo json_encode($friends);

?>

SQL CODE：

SELECT p9_member.member_no,p9_member.photo AS PHOTO
FROM p9_member, p9_friends 
WHERE p9_member.member_no = p9_friends.member_no2 
AND p9_friends.member_no1 =".$_POST['memberno']

json解码后，我无法从应用程序中获取数据。对我来说最好的解决方案是什么？

Answer 1

尝试以下代码，它将起作用..

$image_qry=mysql_query("SELECT * FROM tabel_name WHERE your condition");
$image=mysql_fetch_assoc($image_qry);
$get_image=$image['image_column']; //BLOB DATA TYPE
header("Content-type: image/jpeg"); // need to add the header content type in your code
echo $get_image;

PHP - 从数据库获取图像

1 个答案: