示例在这里http://jsfiddle.net/68z9dkyb/5/
有2个日期选择器。
<input type="text" class="datepicker" id="date_first_registration">
<input type="text" class="datepicker" id="inspection_valid_until">
对于一个想要的日期范围,从今年前100年开始到今年结束。另一个是在一年之前开始,在今年之后的20年结束。
试过这个:
$(function() {
$(".datepicker").datepicker({
inline: true,
showOtherMonths: true,
changeMonth: true,
changeYear: true,
dayNamesMin: ["Sun", "Mon", "Tue", "Wed", "Thu", "Frid ", "Sat"],
dateFormat: "yy-mm-dd"
}).val()
$("#date_first_registration").datepicker({
yearRange: "-100:+0"
}).val()
$("#inspection_valid_until").datepicker({
yearRange: "-1:+20"
}).val()
});
但是不起作用。根据我的理解,我为.datepicker
设置了所有内容,然后为每个ID设置不同的日期范围。但是不起作用。需要纠正什么?
答案 0 :(得分:2)
1:您可以使用option
参数:
$(function() {
$(".datepicker").datepicker({
showOtherMonths: true,
changeMonth: true,
changeYear: true,
dayNamesMin: ["Sun", "Mon", "Tue", "Wed", "Thu", "Frid ", "Sat"],
dateFormat: "yy-mm-dd"
});
$("#date_first_registration").datepicker("option", "yearRange", "-100:+0");
$("#inspection_valid_until").datepicker("option", "yearRange", "-1:+20");
});
@import url("//ajax.googleapis.com/ajax/libs/jqueryui/1.11.1/themes/redmond/jquery-ui.min.css");
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.11.1/jquery-ui.min.js"></script>
<input class="datepicker" id="date_first_registration">
<input class="datepicker" id="inspection_valid_until">
2:替代方法是使用对象和jQuery.extend
:
$(function() {
var defaults = {
showOtherMonths: true,
changeMonth: true,
changeYear: true,
dayNamesMin: ["Sun", "Mon", "Tue", "Wed", "Thu", "Frid ", "Sat"],
dateFormat: "yy-mm-dd"
};
$("#date_first_registration").datepicker($.extend({}, defaults, {
yearRange: "-100:+0"
}));
$("#inspection_valid_until").datepicker($.extend({}, defaults, {
yearRange: "-1:+20"
}));
});
@import url("//ajax.googleapis.com/ajax/libs/jqueryui/1.11.1/themes/redmond/jquery-ui.min.css");
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.11.1/jquery-ui.min.js"></script>
<input class="datepicker" id="date_first_registration">
<input class="datepicker" id="inspection_valid_until">
答案 1 :(得分:1)
删除.datepicker
类通用代码,并为每个日期选择器实现单独的代码,如
$("#date_first_registration").datepicker({
changeMonth: true,
changeYear: true,
dayNamesMin: ["Sun", "Mon", "Tue", "Wed", "Thu", "Frid ", "Sat"],
yearRange: "-100:+0"
}).val()
$("#inspection_valid_until").datepicker({
changeMonth: true,
changeYear: true,
dayNamesMin: ["Sun", "Mon", "Tue", "Wed", "Thu", "Frid ", "Sat"],
yearRange: "-1:+20"
}).val()