Question

我想预先加载这4张图片。我试过这个：

<img src="img/1.jpg" style="display:none">
<img src="img/1a.jpg" style="display:none">
<img src="img/1b.jpg" style="display:none">
<img src="img/1c.jpg" style="display:none">

它没有用，所以我尝试了这个：

new Image().src = "img/1.jpg";
new Image().src = "img/1a.jpg";
new Image().src = "img/1b.jpg";
new Image().src = "img/1c.jpg";

JS方法适用于背景但不适用于这些。

Answer 1

尝试使用$.Deferred()，.queue()

var images = ["http://lorempixel.com/1200/800/cats/"
             , "http://lorempixel.com/1200/800/nature/"
             , "http://lorempixel.com/1200/800/animals/"
             , "http://lorempixel.com/1200/800/technics/"
             ];
    // do stuff when image loaded
    var loadImage = function loadImage(elem) {
      return $(elem).fadeTo(500, "1.0", "linear"); 
    };
    
    // load images
    var loadImages = function loadImages(urls, image, complete) {
        // `this` : `document`
        urls.forEach(function(imageSrc, i) {
          var img = new Image;
          var dfd = new $.Deferred();
          // return `this` : `document`
          dfd.then(function(ready) {
              loadImage(ready);   
              return this
          }, function(error) {
             console.log(error)
          })
          .always(function() {
             console.log(complete, urls.length);
             return urls.length === complete 
                    ? $(this)
                      .data("complete", complete + " images loaded")
                      .dequeue("images") // when all images loaded
                    : this
    
          });
          // log errors
          img.onerror = dfd.reject;
          img.onload = function(e) {
            complete = this.complete ? ++complete : complete;
            dfd.resolveWith(document, [
              image.eq(i).prop("src", this.src)
              ]
            );
    
          };
          img.src = imageSrc
          });
          // return `this` : `document`
          return this
    };
    

    $(window).load(function() {
        // init `loadImages`
        var complete = 0;
        // call `loadImages`,
        // `this` context : `document` 
        loadImages.call(document, images, $(".image"), complete)
    
    });
    
    $(document).ready(function() {
        // notify when all images loaded
        $(this).queue("images", function() {
          console.log($(this).data())
        });               
    });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js">
</script>
<!-- note , `src` attribute not included -->
<img class="image" style="opacity:0.0" alt="1">
<img class="image" style="opacity:0.0" alt="1a">
<img class="image" style="opacity:0.0" alt="1b">
<img class="image" style="opacity:0.0" alt="1c">

Answer 2

这实际上从未向DOM添加任何内容，我使用数组来保存已创建图像的引用，并将它们传递给可选的回调

var paths =  [
    "img/1.jpg",
    "img/1a.jpg",
    "img/1b.jpg",
    "img/1c.jpg"
];

preloadImages(paths);

function preloadImages(paths, callback) {
    var images = [];
    var loaded = 0;

    paths.forEach(function (path) {
        var img = new Image();
        img.src = path;
        img.onload = onImagePreloaded;
        images.push(img);
    });


    function onImagePreloaded() {
        loaded++;
        if (loaded === paths.length && callback) {
             callback(images);
        }
    }
}

Answer 3

不要将图像本身设置为display: none;，而是将其设置在容器上。

CSS：

.preload {
    display: none;
}

HTML：

<div class="preload">
    <img src="img/1.jpg">
    <img src="img/1a.jpg">
    <img src="img/1b.jpg">
    <img src="img/1c.jpg">
</div>

以HTML格式预加载图像

3 个答案: