Question

模型定义如下：

Team = sequelize.define 'team',
  name: Sequelize.STRING

User = sequelize.define 'user',
  name: Sequelize.STRING
  foo: Sequelize.INTEGER

Team.hasMany User
User.belongsTo Team

如何让所有团队都包含foo等于42的用户，而不在结果中包含用户，并且在结果中没有多次相同的团队，即如何生成以下查询？

SELECT DISTINCT team.id, team.name
FROM team
INNER JOIN user ON user.team_id = team.id
WHERE user.foo = 42

修改：查询应为a raw query，即使用raw的{{1}}选项。

Answer 1

要使内部联接在include方法的find*选项中使用required = true。怎么样DISTINCT - 你可以试试这个黑客：

Team.findAll({ 
    attributes: ['DISTINCT team.id','team.name'], // hack with distinct
    include: [{ 
        model: User, 
        required: true, // inner join
        attributes: []  // exclude user fields from select
    }] 
});

使用Sequelize，如何在不包含连接模型的属性的情况下查询模型？

1 个答案: